/* * Licensed to the Apache Software Foundation (ASF) under one or more * contributor license agreements. See the NOTICE file distributed with * this work for additional information regarding copyright ownership. * The ASF licenses this file to You under the Apache License, Version 2.0 * (the "License"); you may not use this file except in compliance with * the License. You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. */ package org.apache.commons.math3.geometry.euclidean.twod; import org.apache.commons.math3.geometry.Point; import org.apache.commons.math3.util.FastMath; /** Simple container for a two-points segment. * @since 3.0 */ public class Segment { /** Start point of the segment. */ private final Vector2D start; /** End point of the segment. */ private final Vector2D end; /** Line containing the segment. */ private final Line line; /** Build a segment. * @param start start point of the segment * @param end end point of the segment * @param line line containing the segment */ public Segment(final Vector2D start, final Vector2D end, final Line line) { this.start = start; this.end = end; this.line = line; } /** Get the start point of the segment. * @return start point of the segment */ public Vector2D getStart() { return start; } /** Get the end point of the segment. * @return end point of the segment */ public Vector2D getEnd() { return end; } /** Get the line containing the segment. * @return line containing the segment */ public Line getLine() { return line; } /** Calculates the shortest distance from a point to this line segment. * <p> * If the perpendicular extension from the point to the line does not * cross in the bounds of the line segment, the shortest distance to * the two end points will be returned. * </p> * * Algorithm adapted from: * <a href="http://www.codeguru.com/forum/printthread.php?s=cc8cf0596231f9a7dba4da6e77c29db3&t=194400&pp=15&page=1"> * Thread @ Codeguru</a> * * @param p to check * @return distance between the instance and the point * @since 3.1 */ public double distance(final Vector2D p) { final double deltaX = end.getX() - start.getX(); final double deltaY = end.getY() - start.getY(); final double r = ((p.getX() - start.getX()) * deltaX + (p.getY() - start.getY()) * deltaY) / (deltaX * deltaX + deltaY * deltaY); // r == 0 => P = startPt // r == 1 => P = endPt // r < 0 => P is on the backward extension of the segment // r > 1 => P is on the forward extension of the segment // 0 < r < 1 => P is on the segment // if point isn't on the line segment, just return the shortest distance to the end points if (r < 0 || r > 1) { final double dist1 = getStart().distance((Point<Euclidean2D>) p); final double dist2 = getEnd().distance((Point<Euclidean2D>) p); return FastMath.min(dist1, dist2); } else { // find point on line and see if it is in the line segment final double px = start.getX() + r * deltaX; final double py = start.getY() + r * deltaY; final Vector2D interPt = new Vector2D(px, py); return interPt.distance((Point<Euclidean2D>) p); } } }