/*
* Copyright (c) 2015, Oracle and/or its affiliates. All rights reserved.
* DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.
*
* This code is free software; you can redistribute it and/or modify it
* under the terms of the GNU General Public License version 2 only, as
* published by the Free Software Foundation. Oracle designates this
* particular file as subject to the "Classpath" exception as provided
* by Oracle in the LICENSE file that accompanied this code.
*
* This code is distributed in the hope that it will be useful, but WITHOUT
* ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or
* FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License
* version 2 for more details (a copy is included in the LICENSE file that
* accompanied this code).
*
* You should have received a copy of the GNU General Public License version
* 2 along with this work; if not, write to the Free Software Foundation,
* Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA.
*
* Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA
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*/
/*
******************************************************************************
*
* Copyright (C) 2009-2014, International Business Machines
* Corporation and others. All Rights Reserved.
*
******************************************************************************
*/
package sun.text.normalizer;
import java.util.ArrayList;
import sun.text.normalizer.UnicodeSet.SpanCondition;
/*
* Implement span() etc. for a set with strings.
* Avoid recursion because of its exponential complexity.
* Instead, try multiple paths at once and track them with an IndexList.
*/
class UnicodeSetStringSpan {
/*
* Which span() variant will be used? The object is either built for one variant and used once,
* or built for all and may be used many times.
*/
public static final int WITH_COUNT = 0x40; // spanAndCount() may be called
public static final int FWD = 0x20;
public static final int BACK = 0x10;
// public static final int UTF16 = 8;
public static final int CONTAINED = 2;
public static final int NOT_CONTAINED = 1;
public static final int ALL = 0x7f;
public static final int FWD_UTF16_CONTAINED = FWD | /* UTF16 | */ CONTAINED;
public static final int FWD_UTF16_NOT_CONTAINED = FWD | /* UTF16 | */NOT_CONTAINED;
public static final int BACK_UTF16_CONTAINED = BACK | /* UTF16 | */ CONTAINED;
public static final int BACK_UTF16_NOT_CONTAINED = BACK | /* UTF16 | */NOT_CONTAINED;
/**
* Special spanLength short values. (since Java has not unsigned byte type)
* All code points in the string are contained in the parent set.
*/
static final short ALL_CP_CONTAINED = 0xff;
/** The spanLength is >=0xfe. */
static final short LONG_SPAN = ALL_CP_CONTAINED - 1;
/** Set for span(). Same as parent but without strings. */
private UnicodeSet spanSet;
/**
* Set for span(not contained).
* Same as spanSet, plus characters that start or end strings.
*/
private UnicodeSet spanNotSet;
/** The strings of the parent set. */
private ArrayList<String> strings;
/** The lengths of span(), spanBack() etc. for each string. */
private short[] spanLengths;
/** Maximum lengths of relevant strings. */
private int maxLength16;
/** Are there strings that are not fully contained in the code point set? */
private boolean someRelevant;
/** Set up for all variants of span()? */
private boolean all;
/** Span helper */
private OffsetList offsets;
/**
* Constructs for all variants of span(), or only for any one variant.
* Initializes as little as possible, for single use.
*/
public UnicodeSetStringSpan(final UnicodeSet set, final ArrayList<String> setStrings, int which) {
spanSet = new UnicodeSet(0, 0x10ffff);
// TODO: With Java 6, just take the parent set's strings as is,
// as a NavigableSet<String>, rather than as an ArrayList copy of the set of strings.
// Then iterate via the first() and higher() methods.
// (We do not want to create multiple Iterator objects in each span().)
// See ICU ticket #7454.
strings = setStrings;
all = (which == ALL);
spanSet.retainAll(set);
if (0 != (which & NOT_CONTAINED)) {
// Default to the same sets.
// addToSpanNotSet() will create a separate set if necessary.
spanNotSet = spanSet;
}
offsets = new OffsetList();
// Determine if the strings even need to be taken into account at all for span() etc.
// If any string is relevant, then all strings need to be used for
// span(longest match) but only the relevant ones for span(while contained).
// TODO: Possible optimization: Distinguish CONTAINED vs. LONGEST_MATCH
// and do not store UTF-8 strings if !thisRelevant and CONTAINED.
// (Only store irrelevant UTF-8 strings for LONGEST_MATCH where they are relevant after all.)
// Also count the lengths of the UTF-8 versions of the strings for memory allocation.
int stringsLength = strings.size();
int i, spanLength;
someRelevant = false;
for (i = 0; i < stringsLength; ++i) {
String string = strings.get(i);
int length16 = string.length();
spanLength = spanSet.span(string, SpanCondition.CONTAINED);
if (spanLength < length16) { // Relevant string.
someRelevant = true;
}
if (/* (0 != (which & UTF16)) && */ length16 > maxLength16) {
maxLength16 = length16;
}
}
if (!someRelevant && (which & WITH_COUNT) == 0) {
return;
}
// Freeze after checking for the need to use strings at all because freezing
// a set takes some time and memory which are wasted if there are no relevant strings.
if (all) {
spanSet.freeze();
}
int spanBackLengthsOffset;
// Allocate a block of meta data.
int allocSize;
if (all) {
// 2 sets of span lengths
allocSize = stringsLength * (2);
} else {
allocSize = stringsLength; // One set of span lengths.
}
spanLengths = new short[allocSize];
if (all) {
// Store span lengths for all span() variants.
spanBackLengthsOffset = stringsLength;
} else {
// Store span lengths for only one span() variant.
spanBackLengthsOffset = 0;
}
// Set the meta data and spanNotSet and write the UTF-8 strings.
for (i = 0; i < stringsLength; ++i) {
String string = strings.get(i);
int length16 = string.length();
spanLength = spanSet.span(string, SpanCondition.CONTAINED);
if (spanLength < length16) { // Relevant string.
if (true /* 0 != (which & UTF16) */) {
if (0 != (which & CONTAINED)) {
if (0 != (which & FWD)) {
spanLengths[i] = makeSpanLengthByte(spanLength);
}
if (0 != (which & BACK)) {
spanLength = length16
- spanSet.spanBack(string, length16, SpanCondition.CONTAINED);
spanLengths[spanBackLengthsOffset + i] = makeSpanLengthByte(spanLength);
}
} else /* not CONTAINED, not all, but NOT_CONTAINED */{
spanLengths[i] = spanLengths[spanBackLengthsOffset + i] = 0; // Only store a relevant/irrelevant
// flag.
}
}
if (0 != (which & NOT_CONTAINED)) {
// Add string start and end code points to the spanNotSet so that
// a span(while not contained) stops before any string.
int c;
if (0 != (which & FWD)) {
c = string.codePointAt(0);
addToSpanNotSet(c);
}
if (0 != (which & BACK)) {
c = string.codePointBefore(length16);
addToSpanNotSet(c);
}
}
} else { // Irrelevant string.
if (all) {
spanLengths[i] = spanLengths[spanBackLengthsOffset + i] = ALL_CP_CONTAINED;
} else {
// All spanXYZLengths pointers contain the same address.
spanLengths[i] = ALL_CP_CONTAINED;
}
}
}
// Finish.
if (all) {
spanNotSet.freeze();
}
}
/**
* Do the strings need to be checked in span() etc.?
*
* @return true if strings need to be checked (call span() here),
* false if not (use a BMPSet for best performance).
*/
public boolean needsStringSpanUTF16() {
return someRelevant;
}
/** For fast UnicodeSet::contains(c). */
public boolean contains(int c) {
return spanSet.contains(c);
}
/**
* Adds a starting or ending string character to the spanNotSet
* so that a character span ends before any string.
*/
private void addToSpanNotSet(int c) {
if (spanNotSet == null || spanNotSet == spanSet) {
if (spanSet.contains(c)) {
return; // Nothing to do.
}
spanNotSet = spanSet.cloneAsThawed();
}
spanNotSet.add(c);
}
/*
* Note: In span() when spanLength==0
* (after a string match, or at the beginning after an empty code point span)
* and in spanNot() and spanNotUTF8(),
* string matching could use a binary search because all string matches are done
* from the same start index.
*
* For UTF-8, this would require a comparison function that returns UTF-16 order.
*
* This optimization should not be necessary for normal UnicodeSets because most sets have no strings, and most sets
* with strings have very few very short strings. For cases with many strings, it might be better to use a different
* API and implementation with a DFA (state machine).
*/
/*
* Algorithm for span(SpanCondition.CONTAINED)
*
* Theoretical algorithm:
* - Iterate through the string, and at each code point boundary:
* + If the code point there is in the set, then remember to continue after it.
* + If a set string matches at the current position, then remember to continue after it.
* + Either recursively span for each code point or string match, or recursively span
* for all but the shortest one and iteratively continue the span with the shortest local match.
* + Remember the longest recursive span (the farthest end point).
* + If there is no match at the current position,
* neither for the code point there nor for any set string,
* then stop and return the longest recursive span length.
*
* Optimized implementation:
*
* (We assume that most sets will have very few very short strings.
* A span using a string-less set is extremely fast.)
*
* Create and cache a spanSet which contains all of the single code points of the original set
* but none of its strings.
*
* - Start with spanLength=spanSet.span(SpanCondition.CONTAINED).
* - Loop:
* + Try to match each set string at the end of the spanLength.
* ~ Set strings that start with set-contained code points
* must be matched with a partial overlap
* because the recursive algorithm would have tried to match them at every position.
* ~ Set strings that entirely consist of set-contained code points
* are irrelevant for span(SpanCondition.CONTAINED)
* because the recursive algorithm would continue after them anyway and
* find the longest recursive match from their end.
* ~ Rather than recursing, note each end point of a set string match.
* + If no set string matched after spanSet.span(),
* then return with where the spanSet.span() ended.
* + If at least one set string matched after spanSet.span(),
* then pop the shortest string match end point and continue the loop,
* trying to match all set strings from there.
* + If at least one more set string matched after a previous string match, then test if the
* code point after the previous string match is also contained in the set.
* Continue the loop with the shortest end point of
* either this code point or a matching set string.
* + If no more set string matched after a previous string match,
* then try another spanLength=spanSet.span(SpanCondition.CONTAINED).
* Stop if spanLength==0, otherwise continue the loop.
*
* By noting each end point of a set string match, the function visits each string position at most once and
* finishes in linear time.
*
* The recursive algorithm may visit the same string position many times
* if multiple paths lead to it and finishes in exponential time.
*/
/*
* Algorithm for span(SIMPLE)
*
* Theoretical algorithm:
* - Iterate through the string, and at each code point boundary:
* + If the code point there is in the set, then remember to continue after it.
* + If a set string matches at the current position, then remember to continue after it.
* + Continue from the farthest match position and ignore all others.
* + If there is no match at the current position, then stop and return the current position.
*
* Optimized implementation:
*
* (Same assumption and spanSet as above.)
*
* - Start with spanLength=spanSet.span(SpanCondition.CONTAINED).
* - Loop:
* + Try to match each set string at the end of the spanLength.
* ~ Set strings that start with set-contained code points
* must be matched with a partial overlap
* because the standard algorithm would have tried to match them earlier.
* ~ Set strings that entirely consist of set-contained code points
* must be matched with a full overlap because the longest-match algorithm
* would hide set string matches that end earlier.
* Such set strings need not be matched earlier inside the code point span
* because the standard algorithm would then have
* continued after the set string match anyway.
* ~ Remember the longest set string match (farthest end point)
* from the earliest starting point.
* + If no set string matched after spanSet.span(),
* then return with where the spanSet.span() ended.
* + If at least one set string matched,
* then continue the loop after the longest match from the earliest position.
* + If no more set string matched after a previous string match,
* then try another spanLength=spanSet.span(SpanCondition.CONTAINED).
* Stop if spanLength==0, otherwise continue the loop.
*/
/**
* Spans a string.
*
* @param s The string to be spanned
* @param start The start index that the span begins
* @param spanCondition The span condition
* @return the limit (exclusive end) of the span
*/
public int span(CharSequence s, int start, SpanCondition spanCondition) {
if (spanCondition == SpanCondition.NOT_CONTAINED) {
return spanNot(s, start, null);
}
int spanLimit = spanSet.span(s, start, SpanCondition.CONTAINED);
if (spanLimit == s.length()) {
return spanLimit;
}
return spanWithStrings(s, start, spanLimit, spanCondition);
}
/**
* Synchronized method for complicated spans using the offsets.
* Avoids synchronization for simple cases.
*
* @param spanLimit = spanSet.span(s, start, CONTAINED)
*/
private synchronized int spanWithStrings(CharSequence s, int start, int spanLimit,
SpanCondition spanCondition) {
// Consider strings; they may overlap with the span.
int initSize = 0;
if (spanCondition == SpanCondition.CONTAINED) {
// Use offset list to try all possibilities.
initSize = maxLength16;
}
offsets.setMaxLength(initSize);
int length = s.length();
int pos = spanLimit, rest = length - spanLimit;
int spanLength = spanLimit - start;
int i, stringsLength = strings.size();
for (;;) {
if (spanCondition == SpanCondition.CONTAINED) {
for (i = 0; i < stringsLength; ++i) {
int overlap = spanLengths[i];
if (overlap == ALL_CP_CONTAINED) {
continue; // Irrelevant string.
}
String string = strings.get(i);
int length16 = string.length();
// Try to match this string at pos-overlap..pos.
if (overlap >= LONG_SPAN) {
overlap = length16;
// While contained: No point matching fully inside the code point span.
overlap = string.offsetByCodePoints(overlap, -1); // Length of the string minus the last code
// point.
}
if (overlap > spanLength) {
overlap = spanLength;
}
int inc = length16 - overlap; // Keep overlap+inc==length16.
for (;;) {
if (inc > rest) {
break;
}
// Try to match if the increment is not listed already.
if (!offsets.containsOffset(inc) && matches16CPB(s, pos - overlap, length, string, length16)) {
if (inc == rest) {
return length; // Reached the end of the string.
}
offsets.addOffset(inc);
}
if (overlap == 0) {
break;
}
--overlap;
++inc;
}
}
} else /* SIMPLE */{
int maxInc = 0, maxOverlap = 0;
for (i = 0; i < stringsLength; ++i) {
int overlap = spanLengths[i];
// For longest match, we do need to try to match even an all-contained string
// to find the match from the earliest start.
String string = strings.get(i);
int length16 = string.length();
// Try to match this string at pos-overlap..pos.
if (overlap >= LONG_SPAN) {
overlap = length16;
// Longest match: Need to match fully inside the code point span
// to find the match from the earliest start.
}
if (overlap > spanLength) {
overlap = spanLength;
}
int inc = length16 - overlap; // Keep overlap+inc==length16.
for (;;) {
if (inc > rest || overlap < maxOverlap) {
break;
}
// Try to match if the string is longer or starts earlier.
if ((overlap > maxOverlap || /* redundant overlap==maxOverlap && */inc > maxInc)
&& matches16CPB(s, pos - overlap, length, string, length16)) {
maxInc = inc; // Longest match from earliest start.
maxOverlap = overlap;
break;
}
--overlap;
++inc;
}
}
if (maxInc != 0 || maxOverlap != 0) {
// Longest-match algorithm, and there was a string match.
// Simply continue after it.
pos += maxInc;
rest -= maxInc;
if (rest == 0) {
return length; // Reached the end of the string.
}
spanLength = 0; // Match strings from after a string match.
continue;
}
}
// Finished trying to match all strings at pos.
if (spanLength != 0 || pos == 0) {
// The position is after an unlimited code point span (spanLength!=0),
// not after a string match.
// The only position where spanLength==0 after a span is pos==0.
// Otherwise, an unlimited code point span is only tried again when no
// strings match, and if such a non-initial span fails we stop.
if (offsets.isEmpty()) {
return pos; // No strings matched after a span.
}
// Match strings from after the next string match.
} else {
// The position is after a string match (or a single code point).
if (offsets.isEmpty()) {
// No more strings matched after a previous string match.
// Try another code point span from after the last string match.
spanLimit = spanSet.span(s, pos, SpanCondition.CONTAINED);
spanLength = spanLimit - pos;
if (spanLength == rest || // Reached the end of the string, or
spanLength == 0 // neither strings nor span progressed.
) {
return spanLimit;
}
pos += spanLength;
rest -= spanLength;
continue; // spanLength>0: Match strings from after a span.
} else {
// Try to match only one code point from after a string match if some
// string matched beyond it, so that we try all possible positions
// and don't overshoot.
spanLength = spanOne(spanSet, s, pos, rest);
if (spanLength > 0) {
if (spanLength == rest) {
return length; // Reached the end of the string.
}
// Match strings after this code point.
// There cannot be any increments below it because UnicodeSet strings
// contain multiple code points.
pos += spanLength;
rest -= spanLength;
offsets.shift(spanLength);
spanLength = 0;
continue; // Match strings from after a single code point.
}
// Match strings from after the next string match.
}
}
int minOffset = offsets.popMinimum(null);
pos += minOffset;
rest -= minOffset;
spanLength = 0; // Match strings from after a string match.
}
}
/**
* Spans a string and counts the smallest number of set elements on any path across the span.
*
* <p>For proper counting, we cannot ignore strings that are fully contained in code point spans.
*
* <p>If the set does not have any fully-contained strings, then we could optimize this
* like span(), but such sets are likely rare, and this is at least still linear.
*
* @param s The string to be spanned
* @param start The start index that the span begins
* @param spanCondition The span condition
* @param outCount The count
* @return the limit (exclusive end) of the span
*/
public int spanAndCount(CharSequence s, int start, SpanCondition spanCondition,
OutputInt outCount) {
if (spanCondition == SpanCondition.NOT_CONTAINED) {
return spanNot(s, start, outCount);
}
// Consider strings; they may overlap with the span,
// and they may result in a smaller count that with just code points.
if (spanCondition == SpanCondition.CONTAINED) {
return spanContainedAndCount(s, start, outCount);
}
// SIMPLE (not synchronized, does not use offsets)
int stringsLength = strings.size();
int length = s.length();
int pos = start;
int rest = length - start;
int count = 0;
while (rest != 0) {
// Try to match the next code point.
int cpLength = spanOne(spanSet, s, pos, rest);
int maxInc = (cpLength > 0) ? cpLength : 0;
// Try to match all of the strings.
for (int i = 0; i < stringsLength; ++i) {
String string = strings.get(i);
int length16 = string.length();
if (maxInc < length16 && length16 <= rest &&
matches16CPB(s, pos, length, string, length16)) {
maxInc = length16;
}
}
// We are done if there is no match beyond pos.
if (maxInc == 0) {
outCount.value = count;
return pos;
}
// Continue from the longest match.
++count;
pos += maxInc;
rest -= maxInc;
}
outCount.value = count;
return pos;
}
private synchronized int spanContainedAndCount(CharSequence s, int start, OutputInt outCount) {
// Use offset list to try all possibilities.
offsets.setMaxLength(maxLength16);
int stringsLength = strings.size();
int length = s.length();
int pos = start;
int rest = length - start;
int count = 0;
while (rest != 0) {
// Try to match the next code point.
int cpLength = spanOne(spanSet, s, pos, rest);
if (cpLength > 0) {
offsets.addOffsetAndCount(cpLength, count + 1);
}
// Try to match all of the strings.
for (int i = 0; i < stringsLength; ++i) {
String string = strings.get(i);
int length16 = string.length();
// Note: If the strings were sorted by length, then we could also
// avoid trying to match if there is already a match of the same length.
if (length16 <= rest && !offsets.hasCountAtOffset(length16, count + 1) &&
matches16CPB(s, pos, length, string, length16)) {
offsets.addOffsetAndCount(length16, count + 1);
}
}
// We are done if there is no match beyond pos.
if (offsets.isEmpty()) {
outCount.value = count;
return pos;
}
// Continue from the nearest match.
int minOffset = offsets.popMinimum(outCount);
count = outCount.value;
pos += minOffset;
rest -= minOffset;
}
outCount.value = count;
return pos;
}
/**
* Span a string backwards.
*
* @param s The string to be spanned
* @param spanCondition The span condition
* @return The string index which starts the span (i.e. inclusive).
*/
public synchronized int spanBack(CharSequence s, int length, SpanCondition spanCondition) {
if (spanCondition == SpanCondition.NOT_CONTAINED) {
return spanNotBack(s, length);
}
int pos = spanSet.spanBack(s, length, SpanCondition.CONTAINED);
if (pos == 0) {
return 0;
}
int spanLength = length - pos;
// Consider strings; they may overlap with the span.
int initSize = 0;
if (spanCondition == SpanCondition.CONTAINED) {
// Use offset list to try all possibilities.
initSize = maxLength16;
}
offsets.setMaxLength(initSize);
int i, stringsLength = strings.size();
int spanBackLengthsOffset = 0;
if (all) {
spanBackLengthsOffset = stringsLength;
}
for (;;) {
if (spanCondition == SpanCondition.CONTAINED) {
for (i = 0; i < stringsLength; ++i) {
int overlap = spanLengths[spanBackLengthsOffset + i];
if (overlap == ALL_CP_CONTAINED) {
continue; // Irrelevant string.
}
String string = strings.get(i);
int length16 = string.length();
// Try to match this string at pos-(length16-overlap)..pos-length16.
if (overlap >= LONG_SPAN) {
overlap = length16;
// While contained: No point matching fully inside the code point span.
int len1 = 0;
len1 = string.offsetByCodePoints(0, 1);
overlap -= len1; // Length of the string minus the first code point.
}
if (overlap > spanLength) {
overlap = spanLength;
}
int dec = length16 - overlap; // Keep dec+overlap==length16.
for (;;) {
if (dec > pos) {
break;
}
// Try to match if the decrement is not listed already.
if (!offsets.containsOffset(dec) && matches16CPB(s, pos - dec, length, string, length16)) {
if (dec == pos) {
return 0; // Reached the start of the string.
}
offsets.addOffset(dec);
}
if (overlap == 0) {
break;
}
--overlap;
++dec;
}
}
} else /* SIMPLE */{
int maxDec = 0, maxOverlap = 0;
for (i = 0; i < stringsLength; ++i) {
int overlap = spanLengths[spanBackLengthsOffset + i];
// For longest match, we do need to try to match even an all-contained string
// to find the match from the latest end.
String string = strings.get(i);
int length16 = string.length();
// Try to match this string at pos-(length16-overlap)..pos-length16.
if (overlap >= LONG_SPAN) {
overlap = length16;
// Longest match: Need to match fully inside the code point span
// to find the match from the latest end.
}
if (overlap > spanLength) {
overlap = spanLength;
}
int dec = length16 - overlap; // Keep dec+overlap==length16.
for (;;) {
if (dec > pos || overlap < maxOverlap) {
break;
}
// Try to match if the string is longer or ends later.
if ((overlap > maxOverlap || /* redundant overlap==maxOverlap && */dec > maxDec)
&& matches16CPB(s, pos - dec, length, string, length16)) {
maxDec = dec; // Longest match from latest end.
maxOverlap = overlap;
break;
}
--overlap;
++dec;
}
}
if (maxDec != 0 || maxOverlap != 0) {
// Longest-match algorithm, and there was a string match.
// Simply continue before it.
pos -= maxDec;
if (pos == 0) {
return 0; // Reached the start of the string.
}
spanLength = 0; // Match strings from before a string match.
continue;
}
}
// Finished trying to match all strings at pos.
if (spanLength != 0 || pos == length) {
// The position is before an unlimited code point span (spanLength!=0),
// not before a string match.
// The only position where spanLength==0 before a span is pos==length.
// Otherwise, an unlimited code point span is only tried again when no
// strings match, and if such a non-initial span fails we stop.
if (offsets.isEmpty()) {
return pos; // No strings matched before a span.
}
// Match strings from before the next string match.
} else {
// The position is before a string match (or a single code point).
if (offsets.isEmpty()) {
// No more strings matched before a previous string match.
// Try another code point span from before the last string match.
int oldPos = pos;
pos = spanSet.spanBack(s, oldPos, SpanCondition.CONTAINED);
spanLength = oldPos - pos;
if (pos == 0 || // Reached the start of the string, or
spanLength == 0 // neither strings nor span progressed.
) {
return pos;
}
continue; // spanLength>0: Match strings from before a span.
} else {
// Try to match only one code point from before a string match if some
// string matched beyond it, so that we try all possible positions
// and don't overshoot.
spanLength = spanOneBack(spanSet, s, pos);
if (spanLength > 0) {
if (spanLength == pos) {
return 0; // Reached the start of the string.
}
// Match strings before this code point.
// There cannot be any decrements below it because UnicodeSet strings
// contain multiple code points.
pos -= spanLength;
offsets.shift(spanLength);
spanLength = 0;
continue; // Match strings from before a single code point.
}
// Match strings from before the next string match.
}
}
pos -= offsets.popMinimum(null);
spanLength = 0; // Match strings from before a string match.
}
}
/**
* Algorithm for spanNot()==span(SpanCondition.NOT_CONTAINED)
*
* Theoretical algorithm:
* - Iterate through the string, and at each code point boundary:
* + If the code point there is in the set, then return with the current position.
* + If a set string matches at the current position, then return with the current position.
*
* Optimized implementation:
*
* (Same assumption as for span() above.)
*
* Create and cache a spanNotSet which contains
* all of the single code points of the original set but none of its strings.
* For each set string add its initial code point to the spanNotSet.
* (Also add its final code point for spanNotBack().)
*
* - Loop:
* + Do spanLength=spanNotSet.span(SpanCondition.NOT_CONTAINED).
* + If the current code point is in the original set, then return the current position.
* + If any set string matches at the current position, then return the current position.
* + If there is no match at the current position, neither for the code point
* there nor for any set string, then skip this code point and continue the loop.
* This happens for set-string-initial code points that were added to spanNotSet
* when there is not actually a match for such a set string.
*
* @param s The string to be spanned
* @param start The start index that the span begins
* @param outCount If not null: Receives the number of code points across the span.
* @return the limit (exclusive end) of the span
*/
private int spanNot(CharSequence s, int start, OutputInt outCount) {
int length = s.length();
int pos = start, rest = length - start;
int stringsLength = strings.size();
int count = 0;
do {
// Span until we find a code point from the set,
// or a code point that starts or ends some string.
int spanLimit;
if (outCount == null) {
spanLimit = spanNotSet.span(s, pos, SpanCondition.NOT_CONTAINED);
} else {
spanLimit = spanNotSet.spanAndCount(s, pos, SpanCondition.NOT_CONTAINED, outCount);
outCount.value = count = count + outCount.value;
}
if (spanLimit == length) {
return length; // Reached the end of the string.
}
pos = spanLimit;
rest = length - spanLimit;
// Check whether the current code point is in the original set,
// without the string starts and ends.
int cpLength = spanOne(spanSet, s, pos, rest);
if (cpLength > 0) {
return pos; // There is a set element at pos.
}
// Try to match the strings at pos.
for (int i = 0; i < stringsLength; ++i) {
if (spanLengths[i] == ALL_CP_CONTAINED) {
continue; // Irrelevant string.
}
String string = strings.get(i);
int length16 = string.length();
if (length16 <= rest && matches16CPB(s, pos, length, string, length16)) {
return pos; // There is a set element at pos.
}
}
// The span(while not contained) ended on a string start/end which is
// not in the original set. Skip this code point and continue.
// cpLength<0
pos -= cpLength;
rest += cpLength;
++count;
} while (rest != 0);
if (outCount != null) {
outCount.value = count;
}
return length; // Reached the end of the string.
}
private int spanNotBack(CharSequence s, int length) {
int pos = length;
int i, stringsLength = strings.size();
do {
// Span until we find a code point from the set,
// or a code point that starts or ends some string.
pos = spanNotSet.spanBack(s, pos, SpanCondition.NOT_CONTAINED);
if (pos == 0) {
return 0; // Reached the start of the string.
}
// Check whether the current code point is in the original set,
// without the string starts and ends.
int cpLength = spanOneBack(spanSet, s, pos);
if (cpLength > 0) {
return pos; // There is a set element at pos.
}
// Try to match the strings at pos.
for (i = 0; i < stringsLength; ++i) {
// Use spanLengths rather than a spanLengths pointer because
// it is easier and we only need to know whether the string is irrelevant
// which is the same in either array.
if (spanLengths[i] == ALL_CP_CONTAINED) {
continue; // Irrelevant string.
}
String string = strings.get(i);
int length16 = string.length();
if (length16 <= pos && matches16CPB(s, pos - length16, length, string, length16)) {
return pos; // There is a set element at pos.
}
}
// The span(while not contained) ended on a string start/end which is
// not in the original set. Skip this code point and continue.
// cpLength<0
pos += cpLength;
} while (pos != 0);
return 0; // Reached the start of the string.
}
static short makeSpanLengthByte(int spanLength) {
// 0xfe==UnicodeSetStringSpan::LONG_SPAN
return spanLength < LONG_SPAN ? (short) spanLength : LONG_SPAN;
}
// Compare strings without any argument checks. Requires length>0.
private static boolean matches16(CharSequence s, int start, final String t, int length) {
int end = start + length;
while (length-- > 0) {
if (s.charAt(--end) != t.charAt(length)) {
return false;
}
}
return true;
}
/**
* Compare 16-bit Unicode strings (which may be malformed UTF-16)
* at code point boundaries.
* That is, each edge of a match must not be in the middle of a surrogate pair.
* @param s The string to match in.
* @param start The start index of s.
* @param limit The limit of the subsequence of s being spanned.
* @param t The substring to be matched in s.
* @param tlength The length of t.
*/
static boolean matches16CPB(CharSequence s, int start, int limit, final String t, int tlength) {
return matches16(s, start, t, tlength)
&& !(0 < start && Character.isHighSurrogate(s.charAt(start - 1)) &&
Character.isLowSurrogate(s.charAt(start)))
&& !((start + tlength) < limit && Character.isHighSurrogate(s.charAt(start + tlength - 1)) &&
Character.isLowSurrogate(s.charAt(start + tlength)));
}
/**
* Does the set contain the next code point?
* If so, return its length; otherwise return its negative length.
*/
static int spanOne(final UnicodeSet set, CharSequence s, int start, int length) {
char c = s.charAt(start);
if (c >= 0xd800 && c <= 0xdbff && length >= 2) {
char c2 = s.charAt(start + 1);
if (UTF16.isTrailSurrogate(c2)) {
int supplementary = UCharacterProperty.getRawSupplementary(c, c2);
return set.contains(supplementary) ? 2 : -2;
}
}
return set.contains(c) ? 1 : -1;
}
static int spanOneBack(final UnicodeSet set, CharSequence s, int length) {
char c = s.charAt(length - 1);
if (c >= 0xdc00 && c <= 0xdfff && length >= 2) {
char c2 = s.charAt(length - 2);
if (UTF16.isLeadSurrogate(c2)) {
int supplementary = UCharacterProperty.getRawSupplementary(c2, c);
return set.contains(supplementary) ? 2 : -2;
}
}
return set.contains(c) ? 1 : -1;
}
/**
* Helper class for UnicodeSetStringSpan.
*
* <p>List of offsets from the current position from where to try matching
* a code point or a string.
* Stores offsets rather than indexes to simplify the code and use the same list
* for both increments (in span()) and decrements (in spanBack()).
*
* <p>Assumption: The maximum offset is limited, and the offsets that are stored at any one time
* are relatively dense, that is,
* there are normally no gaps of hundreds or thousands of offset values.
*
* <p>This class optionally also tracks the minimum non-negative count for each position,
* intended to count the smallest number of elements of any path leading to that position.
*
* <p>The implementation uses a circular buffer of count integers,
* each indicating whether the corresponding offset is in the list,
* and its path element count.
* This avoids inserting into a sorted list of offsets (or absolute indexes)
* and physically moving part of the list.
*
* <p>Note: In principle, the caller should setMaxLength() to
* the maximum of the max string length and U16_LENGTH/U8_LENGTH
* to account for "long" single code points.
*
* <p>Note: An earlier version did not track counts and stored only byte flags.
* With boolean flags, if maxLength were guaranteed to be no more than 32 or 64,
* the list could be stored as bit flags in a single integer.
* Rather than handling a circular buffer with a start list index,
* the integer would simply be shifted when lower offsets are removed.
* UnicodeSet does not have a limit on the lengths of strings.
*/
private static final class OffsetList {
private int[] list;
private int length;
private int start;
public OffsetList() {
list = new int[16]; // default size
}
public void setMaxLength(int maxLength) {
if (maxLength > list.length) {
list = new int[maxLength];
}
clear();
}
public void clear() {
for (int i = list.length; i-- > 0;) {
list[i] = 0;
}
start = length = 0;
}
public boolean isEmpty() {
return (length == 0);
}
/**
* Reduces all stored offsets by delta, used when the current position moves by delta.
* There must not be any offsets lower than delta.
* If there is an offset equal to delta, it is removed.
*
* @param delta [1..maxLength]
*/
public void shift(int delta) {
int i = start + delta;
if (i >= list.length) {
i -= list.length;
}
if (list[i] != 0) {
list[i] = 0;
--length;
}
start = i;
}
/**
* Adds an offset. The list must not contain it yet.
* @param offset [1..maxLength]
*/
public void addOffset(int offset) {
int i = start + offset;
if (i >= list.length) {
i -= list.length;
}
assert list[i] == 0;
list[i] = 1;
++length;
}
/**
* Adds an offset and updates its count.
* The list may already contain the offset.
* @param offset [1..maxLength]
*/
public void addOffsetAndCount(int offset, int count) {
assert count > 0;
int i = start + offset;
if (i >= list.length) {
i -= list.length;
}
if (list[i] == 0) {
list[i] = count;
++length;
} else if (count < list[i]) {
list[i] = count;
}
}
/**
* @param offset [1..maxLength]
*/
public boolean containsOffset(int offset) {
int i = start + offset;
if (i >= list.length) {
i -= list.length;
}
return list[i] != 0;
}
/**
* @param offset [1..maxLength]
*/
public boolean hasCountAtOffset(int offset, int count) {
int i = start + offset;
if (i >= list.length) {
i -= list.length;
}
int oldCount = list[i];
return oldCount != 0 && oldCount <= count;
}
/**
* Finds the lowest stored offset from a non-empty list, removes it,
* and reduces all other offsets by this minimum.
* @return min=[1..maxLength]
*/
public int popMinimum(OutputInt outCount) {
// Look for the next offset in list[start+1..list.length-1].
int i = start, result;
while (++i < list.length) {
int count = list[i];
if (count != 0) {
list[i] = 0;
--length;
result = i - start;
start = i;
if (outCount != null) { outCount.value = count; }
return result;
}
}
// i==list.length
// Wrap around and look for the next offset in list[0..start].
// Since the list is not empty, there will be one.
result = list.length - start;
i = 0;
int count;
while ((count = list[i]) == 0) {
++i;
}
list[i] = 0;
--length;
start = i;
if (outCount != null) { outCount.value = count; }
return result + i;
}
}
}