package test03; import java.util.Stack; public class LinkedList implements List { private Node head; private int size; public void add(Object o){ if (head==null) { head=new Node(o); } else { Node p=head; while(p.next!=null){ p=p.next; } p.next=new Node(o); } ++size; } public void add(int index , Object o){ checkPositionIndex(index); if (index==0) { Node p=head; head=new Node(o); head.next=p; } else { int i=0; Node p=head; while(i<index-1){ p=p.next; ++i; } Node next=p.next; p.next=new Node(o); p.next.next=next; } ++size; } public Object get(int index){ checkPositionIndex(index); if (index==0) { return head.data; } else { int i=0; Node p=head; while(i<index){ p=p.next; ++i; } return p.data; } } public Object remove(int index){ checkPositionIndex(index); Node result; if (index==0) { result=head; head=head.next; } else { int i=0; Node p=head; while(i<index-1){ p=p.next; ++i; } result=p.next; p.next=p.next.next; } --size; return result.data; } public int size(){ return size; } private void checkPositionIndex(int index){ if (index<0||index>size) { throw new IndexOutOfBoundsException("Index: " + index + ", Size: " + size); } } public void addFirst(Object o){ add(0, o); } public void addLast(Object o){ add(size, o); } public Object removeFirst(){ return remove(0); } public Object removeLast(){ return remove(size-1); } public Iterator iterator(){ return new LinkedListIterator(this); } private class LinkedListIterator implements Iterator{ private LinkedList list; private int position; public LinkedListIterator(LinkedList list) { this.list=list; } @Override public boolean hasNext() { if (position+1>size()){ return false; } return true; } @Override public Object next() { return list.get(position++); } } @Override public String toString(){ for (int i = 0; i <size(); i++) { System.out.print(get(i)+","); } return null; } // private static class Node{ Object data; Node next; Node(Object data) { this.data=data; this.next=null; } } /** * 把该链表逆置 * 例如链表为 3->7->10 , 逆置后变为 10->7->3 */ public void reverse(){ Stack<Object> stack=new Stack<>(); while (size()>0) { stack.add(remove(0)); } while (!stack.isEmpty()) { this.add(stack.pop()); } } /** * 删除一个单链表的前半部分 * 例如:list = 2->5->7->8 , 删除以后的值为 7->8 * 如果list = 2->5->7->8->10 ,删除以后的值为7,8,10 */ public void removeFirstHalf(){ for (int i = 0; i < size()/2; i++) { removeFirst(); } } /** * 从第i个元素开始, 删除length 个元素 , 注意i从0开始 * @param i * @param length */ public void remove(int i, int length){ checkPositionIndex(i); checkPositionIndex(i+length-1); for (int j = 0; j < length; j++) { remove(i); } } /** * 假定当前链表和list均包含已升序排列的整数 * 从当前链表中取出那些list所指定的元素 * 例如当前链表 = 11->101->201->301->401->501->601->701 * listB = 1->3->4->6 * 返回的结果应该是[101,301,401,601] * @param list */ public int[] getElements(LinkedList list){ int[] result=new int[list.size]; for (int i = 0; i < list.size; i++) { result[i]=(int)get((Integer)list.get(i)); } return result; } /** * 已知链表中的元素以值递增有序排列,并以单链表作存储结构。 * 从当前链表中中删除在list中出现的元素 * @param list */ public void subtract(LinkedList list){ int k=0; for (int i = size()-1; i >=0; i--) { for (int j = k; j < list.size(); j++) { if (get(i).equals(list.get(j))) { remove(i); k=j; break; } } } } /** * 已知当前链表中的元素以值递增有序排列,并以单链表作存储结构。 * 删除表中所有值相同的多余元素(使得操作后的线性表中所有元素的值均不相同) */ public void removeDuplicateValues(){ for (int i = size()-2; i >=0; i--) { if (get(i).equals(get(i+1))) { remove(i); } } } /** * 已知链表中的元素以值递增有序排列,并以单链表作存储结构。 * 试写一高效的算法,删除表中所有值大于min且小于max的元素(若表中存在这样的元素) * @param min * @param max */ public void removeRange(int min, int max){ int start=-1; int end=-1; for (int i = 0; i < size(); i++) { if ((int)get(i)>min) { start=i; break; } } for (int i = size()-1; i >=0; i--) { if ((int)get(i)<max) { end=i; break; } } if (start!=end&&start!=-1&&end!=-1) { remove(start, end-start+1); } } /** * 假设当前链表和参数list指定的链表均以元素依值递增有序排列(同一表中的元素值各不相同) * 现要求生成新链表C,其元素为当前链表和list中元素的交集,且表C中的元素有依值递增有序排列 * @param list */ public LinkedList intersection( LinkedList list){ LinkedList cList=new LinkedList(); int m=0; for (int i = 0; i < size(); i++) { for (int j = m; j < list.size(); j++) { if (get(i).equals(list.get(j))) { cList.add(get(i)); m=j+1; } } } return cList; } }