package com.vvv.basic; public class LinkedList implements List { private Node<Object> head; private int size; public void add(Object o) { addLast(o); } public void add(int index, Object o) { if (index < 0 || index > size) { throw new IndexOutOfBoundsException(); } if (index == 0) { addFirst(o); return; } if (index == size) { addLast(o); return; } Node<Object> newNode = new Node<Object>(o); Node<Object> node = head; for (int i = 1; i < index; i++) { node = node.next; } newNode.next = node.next; node.next = newNode; size++; } public Object get(int index) { if (index < 0 || index > size) { throw new IndexOutOfBoundsException(); } Node<Object> node = head; for (int i = 0; i < index; i++) { if (node.next != null) { node = node.next; } } Object data = node.data; return data; } public Object remove(int index) { if (index < 0 || index >= size) { throw new IndexOutOfBoundsException(); } if (index == 0) { return removeFirst(); } Node<Object> node = head; Node<Object> pre = head; for (int i = 0; i < index; i++) { if (node.next != null) { pre = node; node = node.next; } } Object obj = node.data; if (head.next == null) { head = null; pre = null; } else if (node.next == null) { pre.next = null; node = null; } else { pre.next = node.next; node.next = null; node = null; } size--; return obj; } public int size() { return size; } public void addFirst(Object o) { Node<Object> node = new Node<Object>(o); node.next = head; head = node; size++; } public void addLast(Object o) { Node<Object> newNode = new Node<Object>(o); if (head == null) { head = newNode; } else { if (head.next == null) { head.next = newNode; } else { Node<Object> node = head; for (int i = 1; i < size; i++) { node = node.next; } node.next = newNode; } } size++; } public Object removeFirst() { if (size <= 0) throw new IndexOutOfBoundsException(); Node<Object> node = head; head = node.next; node.next = null; size--; return node.data; } public Object removeLast() { if (size <= 0) throw new IndexOutOfBoundsException(); Node<Object> node = head; for (int i = 1; i < size - 1; i++) { node = node.next; } Object data = node.next.data; node.next = null; size--; return data; } public Iterator iterator() { return new LinkedListIterator(); } @SuppressWarnings("hiding") private static class Node<Object> { Object data; Node<Object> next; public Node(Object data) { this.data = data; } } private class LinkedListIterator implements Iterator { private Node<Object> node = head; @Override public boolean hasNext() { return node!=null; } @Override public Object next() { Object data = node.data; node = node.next; return data; } public void moveFirst(){ node = head; } } /** * 把该链表逆置 例如链表为 3->7->10 , 逆置后变为 10->7->3 */ public void reverse() { if (size <= 0) { throw new IndexOutOfBoundsException(); } Node<Object> node = head; Node<Object> middleNode = node; int length = size; for (int i = 0; i < length; i++) { if (node.next != null) { node = node.next; addFirst(node.data); } } middleNode.next = null; node = null; size = length; } /** * 删除一个单链表的前半部分 例如:list = 2->5->7->8 , 删除以后的值为 7->8 如果list = 2->5->7->8->10 * ,删除以后的值为7,8,10 */ public void removeFirstHalf() { if (size <= 0) { throw new IndexOutOfBoundsException(); } Node<Object> node = head; Node<Object> pre = head; int count = 0; for (int i = 0; i < size / 2; i++) { pre = node; node = node.next; count++; } head = node; pre.next = null; pre = null; size = size - count; } /** * 从第i个元素开始, 删除length 个元素 , 注意i从0开始 * * @param i * @param length */ public void remove(int i, int length) { if(i<0 || i>=size || length<0 || length>size || (i+length)>size){ throw new IndexOutOfBoundsException(); } Node<Object> node = head; Node<Object> pre = head; Node<Object> posNode = head; for (int j = 0; j < i+length; j++) { if (node.next != null) { pre = node; if(j==(i-1)){ posNode = node; } node = node.next; } } if(i==0){ head = node; }else{ posNode.next = node; } pre.next = null; pre = null; size = size - length; } /** * 假定当前链表和list均包含已升序排列的整数 从当前链表中取出那些list所指定的元素 例如当前链表 = * 11->101->201->301->401->501->601->701 listB = 1->3->4->6 * 返回的结果应该是[101,301,401,601] * * @param list */ public int[] getElements(LinkedList list) { if (list == null || list.size() == 0) { throw new IndexOutOfBoundsException(); } int[] arr = new int[list.size()]; for (int i = 0; i < list.size(); i++) { int index = (Integer) list.get(i); arr[i] = (Integer) get(index); } return arr; } /** * 已知链表中的元素以值递增有序排列,并以单链表作存储结构。 从当前链表中中删除在list中出现的元素 * * @param list */ public void subtract(LinkedList list) { if (list == null || list.size() == 0) { return; } for (int i = 0; i < list.size(); i++) { int o = (Integer) list.get(i); LinkedListIterator it = (LinkedListIterator) this.iterator(); int index = 0; while (it.hasNext()) { int obj = (Integer) it.next(); if (obj == o) { remove(index); it.moveFirst(); break; } index++; } } } /** * 已知当前链表中的元素以值递增有序排列,并以单链表作存储结构。 删除表中所有值相同的多余元素(使得操作后的线性表中所有元素的值均不相同) */ public void removeDuplicateValues() { if (head == null) { return; } Node<Object> node = head; Node<Object> pre = head; while (node.next != null) { node = node.next; int value = (Integer) pre.data; if ((Integer) node.data == value) { if (node.next == null) { pre.next = null; size--; break; } pre.next = node.next; node = node.next; if (node == null) { size--; break; } size--; } pre = pre.next; } } /** * 已知链表中的元素以值递增有序排列,并以单链表作存储结构。 试写一高效的算法,删除表中所有值大于min且小于max的元素(若表中存在这样的元素) * * @param min * @param max */ public void removeRange(int min, int max) { Node<Object> node = head; Node<Object> minNode = null; int count = 0; while (node != null && (Integer) node.data <= min) { minNode = node; node = node.next; } while (node != null && (Integer) node.data < max) { node = node.next; count++; } if (minNode != null) { minNode.next = node; } else { head = node; } size = size - count; } /** * 假设当前链表和参数list指定的链表均以元素依值递增有序排列(同一表中的元素值各不相同) * 现要求生成新链表C,其元素为当前链表和list中元素的交集,且表C中的元素有依值递增有序排列 * * @param list */ public LinkedList intersection(LinkedList list) { if (head == null) { return null; } LinkedList newList = new LinkedList(); Node<Object> node = head; while (node.next != null) { Iterator it = list.iterator(); while (it.hasNext()) { int value = (Integer)it.next(); if ((Integer) node.data == value) { newList.add(value); break; } } node = node.next; } return newList; } }