package com.vvv.basic;
public class LinkedList implements List {
private Node<Object> head;
private int size;
public void add(Object o) {
addLast(o);
}
public void add(int index, Object o) {
if (index < 0 || index > size) {
throw new IndexOutOfBoundsException();
}
if (index == 0) {
addFirst(o);
return;
}
if (index == size) {
addLast(o);
return;
}
Node<Object> newNode = new Node<Object>(o);
Node<Object> node = head;
for (int i = 1; i < index; i++) {
node = node.next;
}
newNode.next = node.next;
node.next = newNode;
size++;
}
public Object get(int index) {
if (index < 0 || index > size) {
throw new IndexOutOfBoundsException();
}
Node<Object> node = head;
for (int i = 0; i < index; i++) {
if (node.next != null) {
node = node.next;
}
}
Object data = node.data;
return data;
}
public Object remove(int index) {
if (index < 0 || index >= size) {
throw new IndexOutOfBoundsException();
}
if (index == 0) {
return removeFirst();
}
Node<Object> node = head;
Node<Object> pre = head;
for (int i = 0; i < index; i++) {
if (node.next != null) {
pre = node;
node = node.next;
}
}
Object obj = node.data;
if (head.next == null) {
head = null;
pre = null;
} else if (node.next == null) {
pre.next = null;
node = null;
} else {
pre.next = node.next;
node.next = null;
node = null;
}
size--;
return obj;
}
public int size() {
return size;
}
public void addFirst(Object o) {
Node<Object> node = new Node<Object>(o);
node.next = head;
head = node;
size++;
}
public void addLast(Object o) {
Node<Object> newNode = new Node<Object>(o);
if (head == null) {
head = newNode;
} else {
if (head.next == null) {
head.next = newNode;
} else {
Node<Object> node = head;
for (int i = 1; i < size; i++) {
node = node.next;
}
node.next = newNode;
}
}
size++;
}
public Object removeFirst() {
if (size <= 0)
throw new IndexOutOfBoundsException();
Node<Object> node = head;
head = node.next;
node.next = null;
size--;
return node.data;
}
public Object removeLast() {
if (size <= 0)
throw new IndexOutOfBoundsException();
Node<Object> node = head;
for (int i = 1; i < size - 1; i++) {
node = node.next;
}
Object data = node.next.data;
node.next = null;
size--;
return data;
}
public Iterator iterator() {
return new LinkedListIterator();
}
@SuppressWarnings("hiding")
private static class Node<Object> {
Object data;
Node<Object> next;
public Node(Object data) {
this.data = data;
}
}
private class LinkedListIterator implements Iterator {
private Node<Object> node = head;
@Override
public boolean hasNext() {
return node!=null;
}
@Override
public Object next() {
Object data = node.data;
node = node.next;
return data;
}
public void moveFirst(){
node = head;
}
}
/**
* 把该链表逆置 例如链表为 3->7->10 , 逆置后变为 10->7->3
*/
public void reverse() {
if (size <= 0) {
throw new IndexOutOfBoundsException();
}
Node<Object> node = head;
Node<Object> middleNode = node;
int length = size;
for (int i = 0; i < length; i++) {
if (node.next != null) {
node = node.next;
addFirst(node.data);
}
}
middleNode.next = null;
node = null;
size = length;
}
/**
* 删除一个单链表的前半部分 例如:list = 2->5->7->8 , 删除以后的值为 7->8 如果list = 2->5->7->8->10
* ,删除以后的值为7,8,10
*/
public void removeFirstHalf() {
if (size <= 0) {
throw new IndexOutOfBoundsException();
}
Node<Object> node = head;
Node<Object> pre = head;
int count = 0;
for (int i = 0; i < size / 2; i++) {
pre = node;
node = node.next;
count++;
}
head = node;
pre.next = null;
pre = null;
size = size - count;
}
/**
* 从第i个元素开始, 删除length 个元素 , 注意i从0开始
*
* @param i
* @param length
*/
public void remove(int i, int length) {
if(i<0 || i>=size || length<0 || length>size || (i+length)>size){
throw new IndexOutOfBoundsException();
}
Node<Object> node = head;
Node<Object> pre = head;
Node<Object> posNode = head;
for (int j = 0; j < i+length; j++) {
if (node.next != null) {
pre = node;
if(j==(i-1)){
posNode = node;
}
node = node.next;
}
}
if(i==0){
head = node;
}else{
posNode.next = node;
}
pre.next = null;
pre = null;
size = size - length;
}
/**
* 假定当前链表和list均包含已升序排列的整数 从当前链表中取出那些list所指定的元素 例如当前链表 =
* 11->101->201->301->401->501->601->701 listB = 1->3->4->6
* 返回的结果应该是[101,301,401,601]
*
* @param list
*/
public int[] getElements(LinkedList list) {
if (list == null || list.size() == 0) {
throw new IndexOutOfBoundsException();
}
int[] arr = new int[list.size()];
for (int i = 0; i < list.size(); i++) {
int index = (Integer) list.get(i);
arr[i] = (Integer) get(index);
}
return arr;
}
/**
* 已知链表中的元素以值递增有序排列,并以单链表作存储结构。 从当前链表中中删除在list中出现的元素
*
* @param list
*/
public void subtract(LinkedList list) {
if (list == null || list.size() == 0) {
return;
}
for (int i = 0; i < list.size(); i++) {
int o = (Integer) list.get(i);
LinkedListIterator it = (LinkedListIterator) this.iterator();
int index = 0;
while (it.hasNext()) {
int obj = (Integer) it.next();
if (obj == o) {
remove(index);
it.moveFirst();
break;
}
index++;
}
}
}
/**
* 已知当前链表中的元素以值递增有序排列,并以单链表作存储结构。 删除表中所有值相同的多余元素(使得操作后的线性表中所有元素的值均不相同)
*/
public void removeDuplicateValues() {
if (head == null) {
return;
}
Node<Object> node = head;
Node<Object> pre = head;
while (node.next != null) {
node = node.next;
int value = (Integer) pre.data;
if ((Integer) node.data == value) {
if (node.next == null) {
pre.next = null;
size--;
break;
}
pre.next = node.next;
node = node.next;
if (node == null) {
size--;
break;
}
size--;
}
pre = pre.next;
}
}
/**
* 已知链表中的元素以值递增有序排列,并以单链表作存储结构。 试写一高效的算法,删除表中所有值大于min且小于max的元素(若表中存在这样的元素)
*
* @param min
* @param max
*/
public void removeRange(int min, int max) {
Node<Object> node = head;
Node<Object> minNode = null;
int count = 0;
while (node != null && (Integer) node.data <= min) {
minNode = node;
node = node.next;
}
while (node != null && (Integer) node.data < max) {
node = node.next;
count++;
}
if (minNode != null) {
minNode.next = node;
} else {
head = node;
}
size = size - count;
}
/**
* 假设当前链表和参数list指定的链表均以元素依值递增有序排列(同一表中的元素值各不相同)
* 现要求生成新链表C,其元素为当前链表和list中元素的交集,且表C中的元素有依值递增有序排列
*
* @param list
*/
public LinkedList intersection(LinkedList list) {
if (head == null) {
return null;
}
LinkedList newList = new LinkedList();
Node<Object> node = head;
while (node.next != null) {
Iterator it = list.iterator();
while (it.hasNext()) {
int value = (Integer)it.next();
if ((Integer) node.data == value) {
newList.add(value);
break;
}
}
node = node.next;
}
return newList;
}
}