package com.coderising.array; import sun.reflect.generics.tree.VoidDescriptor; import java.awt.event.InputMethodListener; import java.awt.image.AreaAveragingScaleFilter; public class ArrayUtil { /** * 给定一个整形数组a , 对该数组的值进行置换 * 例如: a = [7, 9 , 30, 3] , 置换后为 [3, 30, 9,7] * 如果 a = [7, 9, 30, 3, 4] , 置换后为 [4,3, 30 , 9,7] * * @param origin * @return */ public static void reverseArray(int[] origin) { int mid; if (origin.length % 2 == 0) { mid = origin.length / 2 - 1; } else { mid = origin.length / 2; } for (int i = 0; i <= mid; i++) { int temp = origin[i]; origin[i] = origin[origin.length - 1 - i]; origin[origin.length - 1 - i] = temp; } } /** * 现在有如下的一个数组: int oldArr[]={1,3,4,5,0,0,6,6,0,5,4,7,6,7,0,5} * 要求将以上数组中值为0的项去掉,将不为0的值存入一个新的数组,生成的新数组为: * {1,3,4,5,6,6,5,4,7,6,7,5} * * @param oldArray * @return */ public static int[] removeZero(int[] oldArray) { int size = 0; for (int i = 0; i < oldArray.length; i++) { if (oldArray[i] != 0) { size++; } } int[] newArray = new int[size]; int j = 0; for (int i = 0; i < oldArray.length; i++) { if (oldArray[i] != 0) newArray[j++] = oldArray[i]; } return newArray; } /** * 给定两个已经排序好的整形数组, a1和a2 , 创建一个新的数组a3, 使得a3 包含a1和a2 的所有元素, 并且仍然是有序的 * 例如 a1 = [3, 5, 7,8] a2 = [4, 5, 6,7] 则 a3 为[3,4,5,6,7,8] , 注意: 已经消除了重复 * * @param array1 * @param array2 * @return */ public int[] merge(int[] array1, int[] array2) { int[] mergedArray = new int[array1.length + array2.length]; int i = 0; int j = 0; int k = 0; while (i < array1.length) { while (j < array2.length) { if (array1[i] > array2[j]) { mergedArray[k++] = array2[j++]; } else { mergedArray[k++] = array1[i++]; } } } return mergedArray; } /** * 把一个已经存满数据的数组 oldArray的容量进行扩展, 扩展后的新数据大小为oldArray.length + size * 注意,老数组的元素在新数组中需要保持 * 例如 oldArray = [2,3,6] , size = 3,则返回的新数组为 * [2,3,6,0,0,0] * * @param oldArray * @param size * @return */ public int[] grow(int[] oldArray, int size) { int newSize = oldArray.length + size; int[] newArray = new int[newSize]; for (int i = 0; i < oldArray.length; i++) { newArray[i] = oldArray[i]; } return newArray; } /** * 斐波那契数列为:1,1,2,3,5,8,13,21...... ,给定一个最大值, 返回小于该值的数列 * 例如, max = 15 , 则返回的数组应该为 [1,1,2,3,5,8,13] * max = 1, 则返回空数组 [] * * @param max * @return */ public int[] fibonacci(int max) { return null; } /** * 返回小于给定最大值max的所有素数数组 * 例如max = 23, 返回的数组为[2,3,5,7,11,13,17,19] * * @param max * @return */ public int[] getPrimes(int max) { return null; } /** * 所谓“完数”, 是指这个数恰好等于它的因子之和,例如6=1+2+3 * 给定一个最大值max, 返回一个数组, 数组中是小于max 的所有完数 * * @param max * @return */ public int[] getPerfectNumbers(int max) { return null; } /** * 用seperator 把数组 array给连接起来 * 例如array= [3,8,9], seperator = "-" * 则返回值为"3-8-9" * * @param array * @param s * @return */ public String join(int[] array, String seperator) { String s = ""; for (int i = 0; i < array.length; i++) { if (i != array.length - 1) { s += array[i] + seperator; } } s += array[array.length -1]; return s; } public static void main(String[] args) { int[] array = {1, 2, 3, 4, 0, 1, 0, 2}; reverseArray(array); for (int i = 0; i < array.length; i++) System.out.print(array[i]); int[] newArray = removeZero(array); for (int i = 0; i < newArray.length; i++) System.out.print(newArray[i]); } }