package com.byhieg.coding2017.homework312; import com.byhieg.coding2017.homework226.Iterator; import com.byhieg.coding2017.homework226.List; import com.byhieg.utils.bprint.FullPrint; public class LinkedList implements List { private Node head; int size = 0; public void add(Object o) { addLast(o); } public void add(int index, Object o) { checkRangeForAdd(index); if (index == size) { addLast(o); return; } Node nextNode = node(index); Node newNode = new Node(o, nextNode); Node prevNode; if (index == 0) { prevNode = null; } else { prevNode = node(index - 1); } if (prevNode == null) { head = newNode; } else { prevNode.next = newNode; } size++; } private Node node(int index) { Node cursor = head; for (int i = 0; i < index; i++) { cursor = cursor.next; } return cursor; } private void checkRangeForAdd(int index) { if (index > size || index < 0) { throw new IndexOutOfBoundsException("指定的index超过界限"); } } public Object get(int index) { checkRange(index); return node(index).data; } private void checkRange(int index) { if (index >= size || index < 0) { throw new IndexOutOfBoundsException("指定index超过界限"); } } public Object remove(int index) { checkRange(index); Node targetNode = node(index); Object o = targetNode.data; Node prevNode; Node nextNode = targetNode.next; if (index == 0) { prevNode = null; } else { prevNode = node(index - 1); } if (prevNode == null) { head = nextNode; targetNode.next = null; } else { prevNode.next = nextNode; targetNode.next = null; } targetNode.data = null; size--; return o; } public int size() { return size; } public void addFirst(Object o) { Node nextNode = head; Node newNode = new Node(o, nextNode); head = newNode; size++; } public void addLast(Object o) { Node newNode = new Node(o, null); if (size == 0) { head = newNode; } else { Node lastNode = node(size - 1); lastNode.next = newNode; } size++; } public Object removeFirst() { return remove(0); } public Object removeLast() { return remove(size() - 1); } public Iterator iterator() { return new MyIterator(); } private class MyIterator implements Iterator { public Node cursor = head; @Override public boolean hasNext() { return cursor != null; } @Override public Object next() { Object o = cursor.data; cursor = cursor.next; return o; } } private static class Node { Object data; Node next; public Node(Object data, Node next) { this.data = data; this.next = next; } } /** * 把该链表逆置 * 例如链表为 3->7->10 , 逆置后变为 10->7->3 */ public void reverse() { for (int i = 0; i < size() / 2; i++) { if (i == 0) { Object o1 = remove(i); Object o2 = remove(size - i - 1); addFirst(o2); addLast(o1); } else { Object o1 = remove(i); Object o2 = remove(size - i - 1); add(i, o2); add(size - i, o1); } } } /** * 删除一个单链表的前半部分 * 例如:list = 2->5->7->8 , 删除以后的值为 7->8 * 如果list = 2->5->7->8->10 ,删除以后的值为7,8,10 */ public void removeFirstHalf() { for (int i = 0; i < size() / 2; i++) { remove(0); } } /** * 从第i个元素开始, 删除length 个元素 , 注意i从0开始 * * @param i * @param length */ public void remove(int i, int length) { for (int j = 0 ; j < length ;j ++) { remove(i); } } /** * 假定当前链表和list均包含已升序排列的整数 * 从当前链表中取出那些list所指定的元素 * 例如当前链表 = 11->101->201->301->401->501->601->701 * listB = 1->3->4->6 * 返回的结果应该是[101,301,401,601] * * @param list */ public int[] getElements(LinkedList list) { int[] result = new int[list.size()]; int count = 0; for (int i = 0 ; i < list.size();i++) { result[count++] = (int)get((Integer) list.get(i)); } return result; } /** * 已知链表中的元素以值递增有序排列,并以单链表作存储结构。 * 从当前链表中中删除在list中出现的元素 * * @param list */ public void subtract(LinkedList list) { for (int i = 0 ; i < list.size();i++) { for (int j = 0 ;j < size();j++) { if (list.get(i) == get(j)) { remove(j); } } } } /** * 已知当前链表中的元素以值递增有序排列,并以单链表作存储结构。 * 删除表中所有值相同的多余元素(使得操作后的线性表中所有元素的值均不相同) */ public void removeDuplicateValues() { for (int i = 0; i < size();i++) { for (int j = i + 1 ; j < size();j++) { if (get(i) == get(j)){ remove(j); } } } } /** * 已知链表中的元素以值递增有序排列,并以单链表作存储结构。 * 试写一高效的算法,删除表中所有值大于min且小于max的元素(若表中存在这样的元素) * * @param min * @param max */ public void removeRange(int min, int max) { for (int i = 0 ; i < size();i++) { if ((int)get(i) > min && (int)get(i) < max){ remove(i); i--; } } } /** * 假设当前链表和参数list指定的链表均以元素依值递增有序排列(同一表中的元素值各不相同) * 现要求生成新链表C,其元素为当前链表和list中元素的交集,且表C中的元素有依值递增有序排列 * * @param list */ public LinkedList intersection(LinkedList list) { LinkedList result = new LinkedList(); for (int i = 0 ; i < size();i++) { for (int j = 0 ; j < list.size();j++){ if (get(i) == list.get(j)){ result.add(get(i)); } } } return result; } }