package com.coderising.array; import java.util.ArrayList; import java.util.List; public class ArrayUtil { /** * 给定一个整形数组a , 对该数组的值进行置换 例如: a = [7, 9 , 30, 3] , 置换后为 [3, 30, 9,7] 如果 a = [7, 9, 30, 3, 4] , 置换后为 [4,3, 30 , 9,7] * @param origin * @return */ public void reverseArray(int[] origin){ int len = origin.length; for (int i = 0; i < len/2; i++) { int temp = origin[i]; origin[i] = origin[len-1-i]; origin[len-1-i] = temp; } } /** * 现在有如下的一个数组: int oldArr[]={1,3,4,5,0,0,6,6,0,5,4,7,6,7,0,5} * 要求将以上数组中值为0的项去掉,将不为0的值存入一个新的数组,生成的新数组为: * {1,3,4,5,6,6,5,4,7,6,7,5} * @param oldArray * @return */ public int[] removeZero(int[] oldArray){ int slow = 0; for (int i = 0; i < oldArray.length; i++) { if (oldArray[i] != 0) { oldArray[slow++] = oldArray[i]; } } int[] newArray = new int[slow]; for (int i = 0; i < slow; i++) { newArray[i] = oldArray[i]; } return newArray; } /** * 给定两个已经排序好的整形数组, a1和a2 , 创建一个新的数组a3, 使得a3 包含a1和a2 的所有元素, 并且仍然是有序的 * 例如 a1 = [3, 5, 7,8] a2 = [4, 5, 6,7] 则 a3 为[3,4,5,6,7,8] , 注意: 已经消除了重复 * @param array1 * @param array2 * @return */ public int[] merge(int[] array1, int[] array2){ int[] result = new int[array1.length + array2.length]; int i1 = 0 , i2 = 0, i3 = 0; while (i1 < array1.length && i2 < array2.length) { if (array1[i1] == array2[i2]) { result[i3++] = array1[i1++]; i2++; } else if (array1[i1] < array2[i2]) { result[i3++] = array1[i1++]; } else { result[i3++] = array2[i2++]; } } while (i1 < array1.length) { result[i3++] = array1[i1++]; } while (i2 < array2.length) { result[i3++] = array2[i2++]; } int[] finalResult = new int[i3]; for (int i = 0; i < i3; i++) { finalResult[i] = result[i]; } return finalResult; } /** * 把一个已经存满数据的数组 oldArray的容量进行扩展, 扩展后的新数据大小为oldArray.length + size * 注意,老数组的元素在新数组中需要保持 * 例如 oldArray = [2,3,6] , size = 3,则返回的新数组为 * [2,3,6,0,0,0] * @param oldArray * @param size * @return */ public int[] grow(int [] oldArray, int size){ int[] result = new int[oldArray.length + size]; for (int i = 0; i < oldArray.length; i++) { result[i] = oldArray[i]; } return result; } /** * 斐波那契数列为:1,1,2,3,5,8,13,21...... ,给定一个最大值, 返回小于该值的数列 * 例如, max = 15 , 则返回的数组应该为 [1,1,2,3,5,8,13] * max = 1, 则返回空数组 [] * @param max * @return */ public int[] fibonacci(int max){ List<Integer> result = new ArrayList<>(); if (max <= 1) return new int[]{}; if (max < 2) return new int[]{1,1}; result.add(1); //result.add(1); int num = 1, index = 1; while (num < max) { result.add(num); num = result.get(index) + result.get(index - 1); index++; } int[] resArray = new int[result.size()]; for (int i = 0; i < result.size(); i++) { resArray[i] = result.get(i); } return resArray; } /** * 返回小于给定最大值max的所有素数数组 * 例如max = 23, 返回的数组为[2,3,5,7,11,13,17,19] * @param max * @return */ public int[] getPrimes(int max){ List<Integer> result = new ArrayList<>(); boolean[] notPrime = new boolean[max]; for (int i = 2; i < max; i++) { if (!notPrime[i]) result.add(i); for (int j = 2; i*j < max; j++) { notPrime[i*j] = true; } } int[] resArray = new int[result.size()]; for (int i = 0; i < result.size();i++) { resArray[i] = result.get(i); } return resArray; } /** * 所谓“完数”, 是指这个数恰好等于它的因子之和,例如6=1+2+3 * 给定一个最大值max, 返回一个数组, 数组中是小于max 的所有完数 * @param max * @return */ public int[] getPerfectNumbers(int max){ List<Integer> result = new ArrayList<>(); for (int i = 1; i < max; i++) { int sum = 0; for (int j = 1; j < i/2; j++) { if (i % j == 0) { sum += j; } } if (sum == i) result.add(i); } int[] resArray = new int[result.size()]; for (int i = 0; i < result.size(); i++) { resArray[i] = result.get(i); } return resArray; } /** * 用seperator 把数组 array给连接起来 * 例如array= [3,8,9], seperator = "-" * 则返回值为"3-8-9" * @param array * @param s * @return */ public String join(int[] array, String seperator){ if (array == null || array.length == 0) return null; int len = array.length; char[] result = new char[len + seperator.length()*(len - 1)]; int indexA = 0, indexR = 0; while (indexA < array.length && indexR < result.length) { result[indexR++] = (char)array[indexA++]; if (indexA < array.length - 1){ for (int i = 0; i < seperator.length(); i++) { result[indexR++] = seperator.charAt(i); } } } return String.valueOf(result); } }