package com.github.eloiseSJTU.coding2017.array; import java.security.InvalidParameterException; import com.github.eloiseSJTU.coding2017.basic.ArrayList; import com.github.eloiseSJTU.coding2017.basic.List; public class ArrayUtil { /** * 给定一个整形数组a , 对该数组的值进行置换 例如: a = [7, 9 , 30, 3] , 置换后为 [3, 30, 9,7] 如果 a = * [7, 9, 30, 3, 4] , 置换后为 [4,3, 30 , 9,7] * * @param origin * @return */ public void reverseArray(int[] origin) { if (origin == null) { return; } int left = 0; int right = origin.length - 1; while (left < right) { int tmp = origin[left]; origin[left] = origin[right]; origin[right] = tmp; left++; right--; } } /** * 现在有如下的一个数组: int oldArr[]={1,3,4,5,0,0,6,6,0,5,4,7,6,7,0,5} * 要求将以上数组中值为0的项去掉,将不为0的值存入一个新的数组,生成的新数组为: {1,3,4,5,6,6,5,4,7,6,7,5} * * @param oldArray * @return */ public int[] removeZero(int[] oldArray) { if (oldArray == null) { return null; } int count = 0; for (int i = 0; i < oldArray.length; i++) { if (oldArray[i] != 0) { count++; } } int[] newArray = new int[count]; int index = 0; for (int i = 0; i < oldArray.length; i++) { if (oldArray[i] != 0) { newArray[index++] = oldArray[i]; } } return newArray; } /** * 给定两个已经排序好的整形数组, a1和a2 , 创建一个新的数组a3, 使得a3 包含a1和a2 的所有元素, 并且仍然是有序的 例如 a1 = * [3, 5, 7,8] a2 = [4, 5, 6,7] 则 a3 为[3,4,5,6,7,8] , 注意: 已经消除了重复 * * @param array1 * @param array2 * @return */ public int[] merge(int[] array1, int[] array2) { if (array1 == null) { return array2; } if (array2 == null) { return array1; } int len1 = array1.length; int len2 = array2.length; ArrayList arrayList = new ArrayList(); int i = 0; int j = 0; while (i < len1 && j < len2) { if (array1[i] < array2[j]) { arrayList.add(array1[i]); i++; } else if (array1[i] > array2[j]) { arrayList.add(array2[j]); j++; } else { arrayList.add(array1[i]); i++; j++; } } while (i < len1) { arrayList.add(array1[i++]); } while (j < len2) { arrayList.add(array2[j++]); } return toArray(arrayList); } /** * 把一个已经存满数据的数组 oldArray的容量进行扩展, 扩展后的新数据大小为oldArray.length + size * 注意,老数组的元素在新数组中需要保持 例如 oldArray = [2,3,6] , size = 3,则返回的新数组为 * [2,3,6,0,0,0] * * @param oldArray * @param size * @return */ public int[] grow(int[] oldArray, int size) { if (oldArray == null) { return null; } if (size < 0) { throw new InvalidParameterException("size can't be negative"); } int[] newArray = new int[oldArray.length + size]; for (int i = 0; i < oldArray.length; i++) { newArray[i] = oldArray[i]; } return newArray; } /** * 斐波那契数列为:1,1,2,3,5,8,13,21...... ,给定一个最大值, 返回小于该值的数列 例如, max = 15 , * 则返回的数组应该为 [1,1,2,3,5,8,13] max = 1, 则返回空数组 [] * * @param max * @return */ public int[] fibonacci(int max) { if (max <= 1) { return new int[0]; } ArrayList arrayList = new ArrayList(); int a = 1; arrayList.add(a); int b = 1; arrayList.add(b); int c = a + b; while (c < max) { arrayList.add(c); a = b; b = c; c = a + b; } return toArray(arrayList); } /** * 返回小于给定最大值max的所有素数数组 例如max = 23, 返回的数组为[2,3,5,7,11,13,17,19] * * @param max * @return */ public int[] getPrimes(int max) { ArrayList arrayList = new ArrayList(); for (int i = 2; i < max; i++) { boolean pn = true; for (int j = 0; j < arrayList.size(); j++) { if (i % (int) arrayList.get(j) == 0) { pn = false; break; } } if (pn) { arrayList.add(i); } } return toArray(arrayList); } /** * 所谓“完数”, 是指这个数恰好等于它的因子之和,例如6=1+2+3 给定一个最大值max, 返回一个数组, 数组中是小于max 的所有完数 * * @param max * @return */ public int[] getPerfectNumbers(int max) { ArrayList arrayList = new ArrayList(); for (int i = 2; i < max; i++) { int sum = 0; for (int j = 1; j < i; j++) { if (i % j == 0) { sum += j; } } if (sum == i) { arrayList.add(i); } } return toArray(arrayList); } /** * 用seperator 把数组 array给连接起来 例如array= [3,8,9], seperator = "-" 则返回值为"3-8-9" * * @param array * @param s * @return */ public String join(int[] array, String seperator) { if (array == null || array.length == 0) { return ""; } StringBuffer stringBuffer = new StringBuffer(); int i = 0; for (; i < array.length - 1; i++) { stringBuffer.append(array[i] + seperator); } stringBuffer.append(array[i]); return stringBuffer.toString(); } private int[] toArray(List list) { int size = list.size(); int[] result = new int[size]; for (int i = 0; i < size; i++) { result[i] = (int) list.get(i); } return result; } }