/******************************************************************************* * Copyright (c) 2010 Haifeng Li * * Licensed under the Apache License, Version 2.0 (the "License"); * you may not use this file except in compliance with the License. * You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. *******************************************************************************/ package smile.clustering.linkage; /** * Unweighted Pair Group Method with Arithmetic mean (also known as average linkage). * The distance between two clusters is the mean distance between all possible * pairs of nodes in the two clusters. * <p> * In bioinformatics, UPGMA is used for the creation of phenetic trees * (phenograms). UPGMA assumes a constant rate of evolution (molecular * clock hypothesis), and is not a well-regarded method for inferring * relationships unless this assumption has been tested and justified * for the data set being used. * * @author Haifeng Li */ public class UPGMALinkage extends Linkage { /** * The number of samples in each cluster. */ private int[] n; /** * Constructor. * @param proximity the proximity matrix to store the distance measure of * dissimilarity. To save space, we only need the lower half of matrix. */ public UPGMALinkage(double[][] proximity) { this.proximity = proximity; n = new int[proximity.length]; for (int i = 0; i < n.length; i++) n[i] = 1; } @Override public String toString() { return "UPGMA linkage"; } @Override public void merge(int i, int j) { double sum = n[i] + n[j]; for (int k = 0; k < i; k++) { proximity[i][k] = proximity[i][k] * n[i] / sum + d(j, k) * n[j] / sum; } for (int k = i+1; k < proximity.length; k++) { proximity[k][i] = proximity[k][i] * n[i] / sum + d(j, k) * n[j] / sum; } n[i] += n[j]; } }