/* * Copyright (c) 1997, 2006, Oracle and/or its affiliates. All rights reserved. * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER. * * This code is free software; you can redistribute it and/or modify it * under the terms of the GNU General Public License version 2 only, as * published by the Free Software Foundation. Oracle designates this * particular file as subject to the "Classpath" exception as provided * by Oracle in the LICENSE file that accompanied this code. * * This code is distributed in the hope that it will be useful, but WITHOUT * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or * FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License * version 2 for more details (a copy is included in the LICENSE file that * accompanied this code). * * You should have received a copy of the GNU General Public License version * 2 along with this work; if not, write to the Free Software Foundation, * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA. * * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA * or visit www.oracle.com if you need additional information or have any * questions. */ package sun.security.util; import java.util.Comparator; /** * Compare two byte arrays in lexicographical order. * * @author D. N. Hoover */ public class ByteArrayLexOrder implements Comparator<byte[]> { /** * Perform lexicographical comparison of two byte arrays, * regarding each byte as unsigned. That is, compare array entries * in order until they differ--the array with the smaller entry * is "smaller". If array entries are * equal till one array ends, then the longer array is "bigger". * * @param bytes1 first byte array to compare. * @param bytes2 second byte array to compare. * @return negative number if bytes1 < bytes2, 0 if bytes1 == bytes2, * positive number if bytes1 > bytes2. * * @exception <code>ClassCastException</code> * if either argument is not a byte array. */ public final int compare( byte[] bytes1, byte[] bytes2) { int diff; for (int i = 0; i < bytes1.length && i < bytes2.length; i++) { diff = (bytes1[i] & 0xFF) - (bytes2[i] & 0xFF); if (diff != 0) { return diff; } } // if array entries are equal till the first ends, then the // longer is "bigger" return bytes1.length - bytes2.length; } }