/* * Copyright (c) 2016 Vivid Solutions. * * All rights reserved. This program and the accompanying materials * are made available under the terms of the Eclipse Public License v1.0 * and Eclipse Distribution License v. 1.0 which accompanies this distribution. * The Eclipse Public License is available at http://www.eclipse.org/legal/epl-v10.html * and the Eclipse Distribution License is available at * * http://www.eclipse.org/org/documents/edl-v10.php. */ package org.locationtech.jts.operation.valid; import java.util.ArrayList; import java.util.List; import org.locationtech.jts.algorithm.CGAlgorithms; import org.locationtech.jts.geom.Coordinate; import org.locationtech.jts.geom.LinearRing; import org.locationtech.jts.geomgraph.GeometryGraph; import org.locationtech.jts.util.Assert; /** * Tests whether any of a set of {@link LinearRing}s are * nested inside another ring in the set, using a simple O(n^2) * comparison. * * @version 1.7 */ public class SimpleNestedRingTester { private GeometryGraph graph; // used to find non-node vertices private List rings = new ArrayList(); private Coordinate nestedPt; public SimpleNestedRingTester(GeometryGraph graph) { this.graph = graph; } public void add(LinearRing ring) { rings.add(ring); } public Coordinate getNestedPoint() { return nestedPt; } public boolean isNonNested() { for (int i = 0; i < rings.size(); i++) { LinearRing innerRing = (LinearRing) rings.get(i); Coordinate[] innerRingPts = innerRing.getCoordinates(); for (int j = 0; j < rings.size(); j++) { LinearRing searchRing = (LinearRing) rings.get(j); Coordinate[] searchRingPts = searchRing.getCoordinates(); if (innerRing == searchRing) continue; if (! innerRing.getEnvelopeInternal().intersects(searchRing.getEnvelopeInternal())) continue; Coordinate innerRingPt = IsValidOp.findPtNotNode(innerRingPts, searchRing, graph); Assert.isTrue(innerRingPt != null, "Unable to find a ring point not a node of the search ring"); //Coordinate innerRingPt = innerRingPts[0]; boolean isInside = CGAlgorithms.isPointInRing(innerRingPt, searchRingPts); if (isInside) { nestedPt = innerRingPt; return false; } } } return true; } }