/*
* Copyright (c) 2016 Vivid Solutions.
*
* All rights reserved. This program and the accompanying materials
* are made available under the terms of the Eclipse Public License v1.0
* and Eclipse Distribution License v. 1.0 which accompanies this distribution.
* The Eclipse Public License is available at http://www.eclipse.org/legal/epl-v10.html
* and the Eclipse Distribution License is available at
*
* http://www.eclipse.org/org/documents/edl-v10.php.
*/
package org.locationtech.jts.operation.valid;
import java.util.ArrayList;
import java.util.List;
import org.locationtech.jts.algorithm.CGAlgorithms;
import org.locationtech.jts.geom.Coordinate;
import org.locationtech.jts.geom.LinearRing;
import org.locationtech.jts.geomgraph.GeometryGraph;
import org.locationtech.jts.util.Assert;
/**
* Tests whether any of a set of {@link LinearRing}s are
* nested inside another ring in the set, using a simple O(n^2)
* comparison.
*
* @version 1.7
*/
public class SimpleNestedRingTester
{
private GeometryGraph graph; // used to find non-node vertices
private List rings = new ArrayList();
private Coordinate nestedPt;
public SimpleNestedRingTester(GeometryGraph graph)
{
this.graph = graph;
}
public void add(LinearRing ring)
{
rings.add(ring);
}
public Coordinate getNestedPoint() { return nestedPt; }
public boolean isNonNested()
{
for (int i = 0; i < rings.size(); i++) {
LinearRing innerRing = (LinearRing) rings.get(i);
Coordinate[] innerRingPts = innerRing.getCoordinates();
for (int j = 0; j < rings.size(); j++) {
LinearRing searchRing = (LinearRing) rings.get(j);
Coordinate[] searchRingPts = searchRing.getCoordinates();
if (innerRing == searchRing)
continue;
if (! innerRing.getEnvelopeInternal().intersects(searchRing.getEnvelopeInternal()))
continue;
Coordinate innerRingPt = IsValidOp.findPtNotNode(innerRingPts, searchRing, graph);
Assert.isTrue(innerRingPt != null, "Unable to find a ring point not a node of the search ring");
//Coordinate innerRingPt = innerRingPts[0];
boolean isInside = CGAlgorithms.isPointInRing(innerRingPt, searchRingPts);
if (isInside) {
nestedPt = innerRingPt;
return false;
}
}
}
return true;
}
}