/* * Copyright (c) 1998, 2008, Oracle and/or its affiliates. All rights reserved. * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER. * * This code is free software; you can redistribute it and/or modify it * under the terms of the GNU General Public License version 2 only, as * published by the Free Software Foundation. * * This code is distributed in the hope that it will be useful, but WITHOUT * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or * FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License * version 2 for more details (a copy is included in the LICENSE file that * accompanied this code). * * You should have received a copy of the GNU General Public License version * 2 along with this work; if not, write to the Free Software Foundation, * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA. * * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA * or visit www.oracle.com if you need additional information or have any * questions. */ /* */ import java.io.*; class CompressOutputStream extends FilterOutputStream implements CompressConstants { public CompressOutputStream(OutputStream out) { super(out); } // buffer of 6-bit codes to pack into next 32-bit word int buf[] = new int[5]; // number of valid codes pending in buffer int bufPos = 0; public void write(int b) throws IOException { b &= 0xFF; // force argument to a byte int pos = codeTable.indexOf((char)b); if (pos != -1) writeCode(BASE + pos); else { writeCode(RAW); writeCode(b >> 4); writeCode(b & 0xF); } } public void write(byte b[], int off, int len) throws IOException { /* * This is quite an inefficient implementation, because it has to * call the other write method for every byte in the array. It * could be optimized for performance by doing all the processing * in this method. */ for (int i = 0; i < len; i++) write(b[off + i]); } public void flush() throws IOException { while (bufPos > 0) writeCode(NOP); } private void writeCode(int c) throws IOException { buf[bufPos++] = c; if (bufPos == 5) { // write next word when we have 5 codes int pack = (buf[0] << 24) | (buf[1] << 18) | (buf[2] << 12) | (buf[3] << 6) | buf[4]; out.write((pack >>> 24) & 0xFF); out.write((pack >>> 16) & 0xFF); out.write((pack >>> 8) & 0xFF); out.write((pack >>> 0) & 0xFF); bufPos = 0; } } }