// Copyright 2012 Citrix Systems, Inc. Licensed under the
// Apache License, Version 2.0 (the "License"); you may not use this
// file except in compliance with the License. Citrix Systems, Inc.
// reserves all rights not expressly granted by the License.
// You may obtain a copy of the License at http://www.apache.org/licenses/LICENSE-2.0
// Unless required by applicable law or agreed to in writing, software
// distributed under the License is distributed on an "AS IS" BASIS,
// WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
// See the License for the specific language governing permissions and
// limitations under the License.
//
// Automatically generated by addcopyright.py at 04/03/2012
package com.cloud.utils;
public class Pair<T, U> {
T t;
U u;
protected Pair() {
}
public Pair(T t, U u) {
this.t = t;
this.u = u;
}
public T first() {
return t;
}
public U second() {
return u;
}
public U second(U value) {
u = value;
return u;
}
public T first(T value) {
t = value;
return t;
}
public void set(T t, U u) {
this.t = t;
this.u = u;
}
@Override
// Note: This means any two pairs with null for both values will match each
// other but what can I do? This is due to stupid type erasure.
public int hashCode() {
return (t != null ? t.hashCode() : 0) | (u != null ? u.hashCode() : 0);
}
@Override
public boolean equals(Object obj) {
if (!(obj instanceof Pair)) {
return false;
}
Pair<?, ?> that = (Pair<?, ?>)obj;
return (t != null ? t.equals(that.t) : that.t == null) && (u != null ? u.equals(that.u) : that.u == null);
}
@Override
public String toString() {
StringBuilder b = new StringBuilder("P[");
b.append((t != null) ? t.toString() : "null");
b.append(":");
b.append((u != null) ? u.toString() : "null");
b.append("]");
return b.toString();
}
}