// Copyright 2012 Citrix Systems, Inc. Licensed under the // Apache License, Version 2.0 (the "License"); you may not use this // file except in compliance with the License. Citrix Systems, Inc. // reserves all rights not expressly granted by the License. // You may obtain a copy of the License at http://www.apache.org/licenses/LICENSE-2.0 // Unless required by applicable law or agreed to in writing, software // distributed under the License is distributed on an "AS IS" BASIS, // WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. // See the License for the specific language governing permissions and // limitations under the License. // // Automatically generated by addcopyright.py at 04/03/2012 package com.cloud.utils; public class Pair<T, U> { T t; U u; protected Pair() { } public Pair(T t, U u) { this.t = t; this.u = u; } public T first() { return t; } public U second() { return u; } public U second(U value) { u = value; return u; } public T first(T value) { t = value; return t; } public void set(T t, U u) { this.t = t; this.u = u; } @Override // Note: This means any two pairs with null for both values will match each // other but what can I do? This is due to stupid type erasure. public int hashCode() { return (t != null ? t.hashCode() : 0) | (u != null ? u.hashCode() : 0); } @Override public boolean equals(Object obj) { if (!(obj instanceof Pair)) { return false; } Pair<?, ?> that = (Pair<?, ?>)obj; return (t != null ? t.equals(that.t) : that.t == null) && (u != null ? u.equals(that.u) : that.u == null); } @Override public String toString() { StringBuilder b = new StringBuilder("P["); b.append((t != null) ? t.toString() : "null"); b.append(":"); b.append((u != null) ? u.toString() : "null"); b.append("]"); return b.toString(); } }