/* * Copyright (C) 2011 The Guava Authors * * Licensed under the Apache License, Version 2.0 (the "License"); * you may not use this file except in compliance with the License. * You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. */ package com.google.common.math; import static com.google.common.math.MathBenchmarking.ARRAY_MASK; import static com.google.common.math.MathBenchmarking.ARRAY_SIZE; import static com.google.common.math.MathBenchmarking.RANDOM_SOURCE; import static java.math.RoundingMode.CEILING; import com.google.caliper.BeforeExperiment; import com.google.caliper.Benchmark; import com.google.caliper.Param; import java.math.BigInteger; /** * Benchmarks for the non-rounding methods of {@code BigIntegerMath}. * * @author Louis Wasserman */ public class BigIntegerMathBenchmark { private static final int[] factorials = new int[ARRAY_SIZE]; private static final int[] slowFactorials = new int[ARRAY_SIZE]; private static final int[] binomials = new int[ARRAY_SIZE]; @Param({"50", "1000", "10000"}) int factorialBound; @BeforeExperiment void setUp() { for (int i = 0; i < ARRAY_SIZE; i++) { factorials[i] = RANDOM_SOURCE.nextInt(factorialBound); slowFactorials[i] = RANDOM_SOURCE.nextInt(factorialBound); binomials[i] = RANDOM_SOURCE.nextInt(factorials[i] + 1); } } /** * Previous version of BigIntegerMath.factorial, kept for timing purposes. */ private static BigInteger oldSlowFactorial(int n) { if (n <= 20) { return BigInteger.valueOf(LongMath.factorial(n)); } else { int k = 20; return BigInteger.valueOf(LongMath.factorial(k)).multiply(oldSlowFactorial(k, n)); } } /** * Returns the product of {@code n1} exclusive through {@code n2} inclusive. */ private static BigInteger oldSlowFactorial(int n1, int n2) { assert n1 <= n2; if (IntMath.log2(n2, CEILING) * (n2 - n1) < Long.SIZE - 1) { // the result will definitely fit into a long long result = 1; for (int i = n1 + 1; i <= n2; i++) { result *= i; } return BigInteger.valueOf(result); } /* * We want each multiplication to have both sides with approximately the same number of digits. * Currently, we just divide the range in half. */ int mid = (n1 + n2) >>> 1; return oldSlowFactorial(n1, mid).multiply(oldSlowFactorial(mid, n2)); } @Benchmark int slowFactorial(int reps) { int tmp = 0; for (int i = 0; i < reps; i++) { int j = i & ARRAY_MASK; tmp += oldSlowFactorial(slowFactorials[j]).intValue(); } return tmp; } @Benchmark int factorial(int reps) { int tmp = 0; for (int i = 0; i < reps; i++) { int j = i & ARRAY_MASK; tmp += BigIntegerMath.factorial(factorials[j]).intValue(); } return tmp; } @Benchmark int binomial(int reps) { int tmp = 0; for (int i = 0; i < reps; i++) { int j = i & 0xffff; tmp += BigIntegerMath.binomial(factorials[j], binomials[j]).intValue(); } return tmp; } }