/* * Copyright 2003-2016 JetBrains s.r.o. * * Licensed under the Apache License, Version 2.0 (the "License"); * you may not use this file except in compliance with the License. * You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. */ package jetbrains.mps.generator.impl.plan; import jetbrains.mps.generator.impl.MapCfgGroups; import jetbrains.mps.generator.impl.MapCfgGroups.ByModel; import jetbrains.mps.generator.runtime.TemplateMappingConfiguration; import jetbrains.mps.util.Pair; import java.util.ArrayList; import java.util.Collection; import java.util.Collections; import java.util.Comparator; import java.util.List; /** * Igor Alshannikov * Date: Mar 30, 2007 */ public class GenerationPartitioningUtil { public static List<Pair<String, TemplateMappingConfiguration>> toStrings(Collection<TemplateMappingConfiguration> mappings) { List<Pair<String, TemplateMappingConfiguration>> strings = new ArrayList<Pair<String, TemplateMappingConfiguration>>(); for (ByModel g : new MapCfgGroups(mappings).groupByModel()) { if (g.includesAll()) { // as long as we start with set of MCs, it's impossible to get group with no MCs in it, findAny() is fine. strings.add(new Pair<>(g.getKey().getLongName() + ".*", g.getElements().findAny().get())); } else { String tmName = g.getKey().getLongName() + "."; g.getElements().map(mc -> new Pair<>(tmName + mc.getName(), mc)).forEach(strings::add); } } Collections.sort(strings, Comparator.comparing(Pair.first())); return strings; } }