/* * Copyright (C) 2011 eXo Platform SAS. * * This is free software; you can redistribute it and/or modify it * under the terms of the GNU Lesser General Public License as * published by the Free Software Foundation; either version 2.1 of * the License, or (at your option) any later version. * * This software is distributed in the hope that it will be useful, * but WITHOUT ANY WARRANTY; without even the implied warranty of * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU * Lesser General Public License for more details. * * You should have received a copy of the GNU Lesser General Public * License along with this software; if not, write to the Free * Software Foundation, Inc., 51 Franklin St, Fifth Floor, Boston, MA * 02110-1301 USA, or see the FSF site: http://www.fsf.org. */ package org.exoplatform.portal.mop.user; /** * A set of utils for this package. * * @author <a href="mailto:julien.viet@exoplatform.com">Julien Viet</a> */ class Utils { /** * Parse the path with the following algorithm: * * <ul> * <li>The one char <code>/</code> string returns the null array</li> * <li>Any leading <code>/<code> char is ommited</li> * <li>Any trailing </code>/</code> chars are ommited</li> * <li>All the substrings obtained by slicing the remaining string by the <code>/</code> char are returned as an array, even * the empty strings</li> * </ul> * * <p> * Note that this is a reimplementation of a previous method that was using regex splitting, this reimplementation was done * in order to minimize the created object count in mind and attempt to create the minimum required. * </p> * * @param path the path * @return the parse result * @throws NullPointerException if the path argument is null */ static String[] parsePath(String path) throws NullPointerException { // Where we start final int start = 0 < path.length() && path.charAt(0) == '/' ? 1 : 0; // if (start == path.length()) { return null; } // Where we end int end = path.length(); while (end > start && path.charAt(end - 1) == '/') { end--; } // Count the number of slash int count = 0; int i = start; while (true) { int pos = path.indexOf('/', i); if (pos == -1) { pos = end; } if (pos == end) { if (pos > i) { count++; } break; } else { count++; i = pos + 1; } } // Now fill the array String[] names = new String[count]; i = start; int index = 0; while (true) { int pos = path.indexOf('/', i); if (pos == -1) { pos = end; } if (pos == end) { if (pos > i) { names[index] = path.substring(i, end); } break; } else { if (i < pos) { names[index++] = path.substring(i, pos); } else { names[index++] = ""; } i = pos + 1; } } // return names; } }