/*
* Copyright 2010-2016 Amazon.com, Inc. or its affiliates. All Rights Reserved.
*
* Portions copyright 2006-2009 James Murty. Please see LICENSE.txt
* for applicable license terms and NOTICE.txt for applicable notices.
*
* Licensed under the Apache License, Version 2.0 (the "License").
* You may not use this file except in compliance with the License.
* A copy of the License is located at
*
* http://aws.amazon.com/apache2.0
*
* or in the "license" file accompanying this file. This file is distributed
* on an "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either
* express or implied. See the License for the specific language governing
* permissions and limitations under the License.
*/
package com.amazonaws.services.polly.internal;
import com.amazonaws.AmazonClientException;
import com.amazonaws.Request;
import com.amazonaws.util.HttpUtils;
import java.net.MalformedURLException;
import java.net.URL;
import java.util.Map;
/**
* General utility methods used throughout the Amazon Polly Android client.
*/
public class ServiceUtils {
/**
* Converts the specified request object into a URL, containing all the
* specified parameters, the specified request endpoint, etc.
*
* @param request The request to convert into a URL.
* @param removeLeadingSlashInResourcePath Whether the leading slash in
* resource-path should be removed before appending to the
* endpoint.
* @return A new URL representing the specified request.
* @throws AmazonClientException If the request cannot be converted to a
* well formed URL.
*/
public static URL convertRequestToUrl(Request<?> request,
boolean removeLeadingSlashInResourcePath) {
String resourcePath = HttpUtils.urlEncode(request.getResourcePath(), true);
// Removed the padding "/" that was already added into the request's
// resource path.
if (removeLeadingSlashInResourcePath
&& resourcePath.startsWith("/")) {
resourcePath = resourcePath.substring(1);
}
// Some http client libraries (e.g. Apache HttpClient) cannot handle
// consecutive "/"s between URL authority and path components.
// So we escape "////..." into "/%2F%2F%2F..."
String urlPath = "/" + resourcePath;
urlPath = urlPath.replaceAll("(?<=/)/", "%2F");
String urlString = request.getEndpoint() + urlPath;
boolean firstParam = true;
Map<String, String> parameters = request.getParameters();
for (String param : parameters.keySet()) {
if (firstParam) {
urlString += "?";
firstParam = false;
} else {
urlString += "&";
}
String value = parameters.get(param);
urlString += param + "=" + HttpUtils.urlEncode(value, false);
}
try {
return new URL(urlString);
} catch (MalformedURLException e) {
throw new AmazonClientException(
"Unable to convert request to well formed URL: " + e.getMessage(), e);
}
}
}