package com.freetymekiyan.algorithms.level.medium; import java.util.ArrayList; import java.util.List; /** * 120. Triangle * Given a triangle, find the minimum path sum from top to bottom. Each step you may move to adjacent numbers on the row * below. * For example, given the following triangle * [ * [2], * [3,4], * [6,5,7], * [4,1,8,3] * ] * The minimum path sum from top to bottom is 11 (i.e., 2 + 3 + 5 + 1 = 11). * Note: * Bonus point if you are able to do this using only O(n) extra space, where n is the total number of rows in the * triangle. * Tags: Array Dynamic Programming * Analysis: DP * * @author chenshuna */ class Triangle_shuna { public static int minimumTotalBottonUp(List<List<Integer>> triangle) { int[] dp = new int[triangle.size() + 1]; for (int i = triangle.size() - 1; i >= 0; i--) { for (int j = 0; j < triangle.get(i).size(); j++) { dp[j] = triangle.get(i).get(j) + Math.min(dp[j], dp[j + 1]); } } return dp[0]; } public static int minimumTotal(List<List<Integer>> triangle) { int minSum = Integer.MAX_VALUE; int[] sum = new int[triangle.size()]; sum[0] = triangle.get(0).get(0); for (int i = 1; i < triangle.size(); i++) { // from top to bottom List<Integer> line = triangle.get(i); for (int j = i; j >= 0; j--) { if (j == 0) { sum[j] += line.get(j); } else if (j == i) { sum[j] = sum[j - 1] + line.get(j); } else { sum[j] = Math.min(sum[j], sum[j - 1]) + line.get(j); } } } for (int cnt : sum) { minSum = Math.min(minSum, cnt); } return minSum; } public static void main(String[] args) { List<List<Integer>> test1 = new ArrayList<>(); List<Integer> test3 = new ArrayList<Integer>(); test3.add(4); test1.add(test3); List<Integer> test4 = new ArrayList<Integer>(); test4.add(5); test4.add(7); test1.add(test4); List<Integer> test5 = new ArrayList<Integer>(); test5.add(1); test5.add(8); test5.add(3); test1.add(test5); System.out.print(minimumTotal(test1)); } }