/*
* Copyright (C) 2011 eXo Platform SAS.
*
* This is free software; you can redistribute it and/or modify it
* under the terms of the GNU Lesser General Public License as
* published by the Free Software Foundation; either version 2.1 of
* the License, or (at your option) any later version.
*
* This software is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
* Lesser General Public License for more details.
*
* You should have received a copy of the GNU Lesser General Public
* License along with this software; if not, write to the Free
* Software Foundation, Inc., 51 Franklin St, Fifth Floor, Boston, MA
* 02110-1301 USA, or see the FSF site: http://www.fsf.org.
*/
package org.exoplatform.portal.mop.user;
/**
* A set of utils for this package.
*
* @author <a href="mailto:julien.viet@exoplatform.com">Julien Viet</a>
*/
class Utils
{
/**
* Parse the path with the following algorithm:
*
* <ul>
* <li>The one char <code>/</code> string returns the null array</li>
* <li>Any leading <code>/<code> char is ommited</li>
* <li>Any trailing </code>/</code> chars are ommited</li>
* <li>All the substrings obtained by slicing the remaining string by the <code>/</code> char are returned
* as an array, even the empty strings</li>
* </ul>
*
* <p>Note that this is a reimplementation of a previous method that was using regex splitting, this reimplementation
* was done in order to minimize the created object count in mind and attempt to create the minimum required.</p>
*
* @param path the path
* @return the parse result
* @throws NullPointerException if the path argument is null
*/
static String[] parsePath(String path) throws NullPointerException
{
// Where we start
final int start = 0 < path.length() && path.charAt(0) == '/' ? 1 : 0;
//
if (start == path.length())
{
return null;
}
// Where we end
int end = path.length();
while (end > start && path.charAt(end - 1) == '/')
{
end--;
}
// Count the number of slash
int count = 0;
int i = start;
while (true)
{
int pos = path.indexOf('/', i);
if (pos == -1)
{
pos = end;
}
if (pos == end)
{
if (pos > i)
{
count++;
}
break;
}
else
{
count++;
i = pos + 1;
}
}
// Now fill the array
String[] names = new String[count];
i = start;
int index = 0;
while (true)
{
int pos = path.indexOf('/', i);
if (pos == -1)
{
pos = end;
}
if (pos == end)
{
if (pos > i)
{
names[index] = path.substring(i, end);
}
break;
}
else
{
if (i < pos)
{
names[index++] = path.substring(i, pos);
}
else
{
names[index++] = "";
}
i = pos + 1;
}
}
//
return names;
}
}