package com.fasterxml.jackson.core.type; import java.lang.reflect.ParameterizedType; import java.lang.reflect.Type; /** * This generic abstract class is used for obtaining full generics type information * by sub-classing; it must be converted to {@link ResolvedType} implementation * (implemented by <code>JavaType</code> from "databind" bundle) to be used. * Class is based on ideas from * <a href="http://gafter.blogspot.com/2006/12/super-type-tokens.html" * >http://gafter.blogspot.com/2006/12/super-type-tokens.html</a>, * Additional idea (from a suggestion made in comments of the article) * is to require bogus implementation of <code>Comparable</code> * (any such generic interface would do, as long as it forces a method * with generic type to be implemented). * to ensure that a Type argument is indeed given. *<p> * Usage is by sub-classing: here is one way to instantiate reference * to generic type <code>List<Integer></code>: *<pre> * TypeReference ref = new TypeReference<List<Integer>>() { }; *</pre> * which can be passed to methods that accept TypeReference, or resolved * using <code>TypeFactory</code> to obtain {@link ResolvedType}. */ public abstract class TypeReference<T> implements Comparable<TypeReference<T>> { protected final Type _type; protected TypeReference() { Type superClass = getClass().getGenericSuperclass(); if (superClass instanceof Class<?>) { // sanity check, should never happen throw new IllegalArgumentException("Internal error: TypeReference constructed without actual type information"); } /* 22-Dec-2008, tatu: Not sure if this case is safe -- I suspect * it is possible to make it fail? * But let's deal with specific * case when we know an actual use case, and thereby suitable * workarounds for valid case(s) and/or error to throw * on invalid one(s). */ _type = ((ParameterizedType) superClass).getActualTypeArguments()[0]; } public Type getType() { return _type; } /** * The only reason we define this method (and require implementation * of <code>Comparable</code>) is to prevent constructing a * reference without type information. */ // @Override public int compareTo(TypeReference<T> o) { // just need an implementation, not a good one... hence: return 0; } }