/**
* Copyright (C) 2010-2017 Gordon Fraser, Andrea Arcuri and EvoSuite
* contributors
*
* This file is part of EvoSuite.
*
* EvoSuite is free software: you can redistribute it and/or modify it
* under the terms of the GNU Lesser General Public License as published
* by the Free Software Foundation, either version 3.0 of the License, or
* (at your option) any later version.
*
* EvoSuite is distributed in the hope that it will be useful, but
* WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
* Lesser Public License for more details.
*
* You should have received a copy of the GNU Lesser General Public
* License along with EvoSuite. If not, see <http://www.gnu.org/licenses/>.
*/
package org.evosuite.utils;
import org.apache.commons.lang3.StringEscapeUtils;
public abstract class StringUtil {
public static String getEscapedString(String original) {
char[] charArray = StringEscapeUtils.escapeJava((String) original).toCharArray();
StringBuilder sb = new StringBuilder();
for (int i = 0; i < charArray.length; ++i) {
char a = charArray[i];
if (a > 255) {
sb.append("\\u");
sb.append(Integer.toHexString(a));
} else {
sb.append(a);
}
}
return sb.toString();
}
/**
* <p>escapeQuotes</p>
*
* @param str a {@link java.lang.String} object.
* @return a {@link java.lang.String} object.
*/
public static String escapeQuotes(String str) {
return str.replaceAll("['\"\\\\]", "\\\\$0");
}
/**
* Compares all Strings in an array and returns the initial sequence of
* characters that is common to all of them.
*
* For example,
* <code>getCommonPrefix(new String[] {"i am a machine", "i am a robot"}) -> "i am a "</code>
*
* <pre>
* StringUtils.getCommonPrefix(null) = ""
* StringUtils.getCommonPrefix(new String[] {}) = ""
* StringUtils.getCommonPrefix(new String[] {"abc"}) = "abc"
* StringUtils.getCommonPrefix(new String[] {null, null}) = ""
* StringUtils.getCommonPrefix(new String[] {"", ""}) = ""
* StringUtils.getCommonPrefix(new String[] {"", null}) = ""
* StringUtils.getCommonPrefix(new String[] {"abc", null, null}) = ""
* StringUtils.getCommonPrefix(new String[] {null, null, "abc"}) = ""
* StringUtils.getCommonPrefix(new String[] {"", "abc"}) = ""
* StringUtils.getCommonPrefix(new String[] {"abc", ""}) = ""
* StringUtils.getCommonPrefix(new String[] {"abc", "abc"}) = "abc"
* StringUtils.getCommonPrefix(new String[] {"abc", "a"}) = "a"
* StringUtils.getCommonPrefix(new String[] {"ab", "abxyz"}) = "ab"
* StringUtils.getCommonPrefix(new String[] {"abcde", "abxyz"}) = "ab"
* StringUtils.getCommonPrefix(new String[] {"abcde", "xyz"}) = ""
* StringUtils.getCommonPrefix(new String[] {"xyz", "abcde"}) = ""
* StringUtils.getCommonPrefix(new String[] {"i am a machine", "i am a robot"}) = "i am a "
* </pre>
*
* @param strs
* array of String objects, entries may be null
* @return the initial sequence of characters that are common to all Strings
* in the array; empty String if the array is null, the elements are
* all null or if there is no common prefix.
* @since 2.4
*/
public static String getCommonPrefix(String[] strs) {
if (strs == null || strs.length == 0) {
return "";
}
int smallestIndexOfDiff = indexOfDifference(strs);
if (smallestIndexOfDiff == -1) {
// all strings were identical
if (strs[0] == null) {
return "";
}
return strs[0];
} else if (smallestIndexOfDiff == 0) {
// there were no common initial characters
return "";
} else {
// we found a common initial character sequence
return strs[0].substring(0, smallestIndexOfDiff);
}
}
/**
* Compares all Strings in an array and returns the index at which the
* Strings begin to differ.
*
* For example,
* <code>indexOfDifference(new String[] {"i am a machine", "i am a robot"}) -> 7</code>
*
* <pre>
* StringUtils.indexOfDifference(null) = -1
* StringUtils.indexOfDifference(new String[] {}) = -1
* StringUtils.indexOfDifference(new String[] {"abc"}) = -1
* StringUtils.indexOfDifference(new String[] {null, null}) = -1
* StringUtils.indexOfDifference(new String[] {"", ""}) = -1
* StringUtils.indexOfDifference(new String[] {"", null}) = 0
* StringUtils.indexOfDifference(new String[] {"abc", null, null}) = 0
* StringUtils.indexOfDifference(new String[] {null, null, "abc"}) = 0
* StringUtils.indexOfDifference(new String[] {"", "abc"}) = 0
* StringUtils.indexOfDifference(new String[] {"abc", ""}) = 0
* StringUtils.indexOfDifference(new String[] {"abc", "abc"}) = -1
* StringUtils.indexOfDifference(new String[] {"abc", "a"}) = 1
* StringUtils.indexOfDifference(new String[] {"ab", "abxyz"}) = 2
* StringUtils.indexOfDifference(new String[] {"abcde", "abxyz"}) = 2
* StringUtils.indexOfDifference(new String[] {"abcde", "xyz"}) = 0
* StringUtils.indexOfDifference(new String[] {"xyz", "abcde"}) = 0
* StringUtils.indexOfDifference(new String[] {"i am a machine", "i am a robot"}) = 7
* </pre>
*
* @param strs
* array of strings, entries may be null
* @return the index where the strings begin to differ; -1 if they are all
* equal
* @since 2.4
*/
public static int indexOfDifference(String[] strs) {
if (strs == null || strs.length <= 1) {
return -1;
}
boolean anyStringNull = false;
boolean allStringsNull = true;
int arrayLen = strs.length;
int shortestStrLen = Integer.MAX_VALUE;
int longestStrLen = 0;
// find the min and max string lengths; this avoids checking to make
// sure we are not exceeding the length of the string each time through
// the bottom loop.
for (int i = 0; i < arrayLen; i++) {
if (strs[i] == null) {
anyStringNull = true;
shortestStrLen = 0;
} else {
allStringsNull = false;
shortestStrLen = Math.min(strs[i].length(), shortestStrLen);
longestStrLen = Math.max(strs[i].length(), longestStrLen);
}
}
// handle lists containing all nulls or all empty strings
if (allStringsNull || (longestStrLen == 0 && !anyStringNull)) {
return -1;
}
// handle lists containing some nulls or some empty strings
if (shortestStrLen == 0) {
return 0;
}
// find the position with the first difference across all strings
int firstDiff = -1;
for (int stringPos = 0; stringPos < shortestStrLen; stringPos++) {
char comparisonChar = strs[0].charAt(stringPos);
for (int arrayPos = 1; arrayPos < arrayLen; arrayPos++) {
if (strs[arrayPos].charAt(stringPos) != comparisonChar) {
firstDiff = stringPos;
break;
}
}
if (firstDiff != -1) {
break;
}
}
if (firstDiff == -1 && shortestStrLen != longestStrLen) {
// we compared all of the characters up to the length of the
// shortest string and didn't find a match, but the string lengths
// vary, so return the length of the shortest string.
return shortestStrLen;
}
return firstDiff;
}
}