/*
* Copyright 2003-2016 JetBrains s.r.o.
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file except in compliance with the License.
* You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
*/
package jetbrains.mps.generator.impl.plan;
import jetbrains.mps.generator.impl.MapCfgGroups;
import jetbrains.mps.generator.impl.MapCfgGroups.ByModel;
import jetbrains.mps.generator.runtime.TemplateMappingConfiguration;
import jetbrains.mps.util.Pair;
import java.util.ArrayList;
import java.util.Collection;
import java.util.Collections;
import java.util.Comparator;
import java.util.List;
/**
* Igor Alshannikov
* Date: Mar 30, 2007
*/
public class GenerationPartitioningUtil {
public static List<Pair<String, TemplateMappingConfiguration>> toStrings(Collection<TemplateMappingConfiguration> mappings) {
List<Pair<String, TemplateMappingConfiguration>> strings = new ArrayList<Pair<String, TemplateMappingConfiguration>>();
for (ByModel g : new MapCfgGroups(mappings).groupByModel()) {
if (g.includesAll()) {
// as long as we start with set of MCs, it's impossible to get group with no MCs in it, findAny() is fine.
strings.add(new Pair<>(g.getKey().getLongName() + ".*", g.getElements().findAny().get()));
} else {
String tmName = g.getKey().getLongName() + ".";
g.getElements().map(mc -> new Pair<>(tmName + mc.getName(), mc)).forEach(strings::add);
}
}
Collections.sort(strings, Comparator.comparing(Pair.first()));
return strings;
}
}