package com.jaeksoft.searchlib.util; import java.awt.Graphics2D; import java.awt.color.ColorSpace; import java.awt.image.BufferedImage; import java.awt.image.ColorConvertOp; /* * pHash-like image hash. * Author: Elliot Shepherd (elliot@jarofworms.com * Based On: http://www.hackerfactor.com/blog/index.php?/archives/432-Looks-Like-It.html */ public class ImagePHash { private int size = 32; private int smallerSize = 8; public ImagePHash() { initCoefficients(); } public ImagePHash(int size, int smallerSize) { this.size = size; this.smallerSize = smallerSize; initCoefficients(); } public int distance(String s1, String s2) { int counter = 0; for (int k = 0; k < s1.length(); k++) { if (s1.charAt(k) != s2.charAt(k)) { counter++; } } return counter; } // Returns a 'binary string' (like. 001010111011100010) which is easy to do // a hamming distance on. public String getHash(BufferedImage img) { /* * 1. Reduce size. Like Average Hash, pHash starts with a small image. * However, the image is larger than 8x8; 32x32 is a good size. This is * really done to simplify the DCT computation and not because it is * needed to reduce the high frequencies. */ img = resize(img, size, size); /* * 2. Reduce color. The image is reduced to a grayscale just to further * simplify the number of computations. */ img = grayscale(img); double[][] vals = new double[size][size]; for (int x = 0; x < img.getWidth(); x++) { for (int y = 0; y < img.getHeight(); y++) { vals[x][y] = getBlue(img, x, y); } } /* * 3. Compute the DCT. The DCT separates the image into a collection of * frequencies and scalars. While JPEG uses an 8x8 DCT, this algorithm * uses a 32x32 DCT. */ // long start = System.currentTimeMillis(); double[][] dctVals = applyDCT(vals); // System.out.println("DCT: " + (System.currentTimeMillis() - start)); /* * 4. Reduce the DCT. This is the magic step. While the DCT is 32x32, * just keep the top-left 8x8. Those represent the lowest frequencies in * the picture. */ /* * 5. Compute the average value. Like the Average Hash, compute the mean * DCT value (using only the 8x8 DCT low-frequency values and excluding * the first term since the DC coefficient can be significantly * different from the other values and will throw off the average). */ double total = 0; for (int x = 0; x < smallerSize; x++) { for (int y = 0; y < smallerSize; y++) { total += dctVals[x][y]; } } total -= dctVals[0][0]; double avg = total / (double) ((smallerSize * smallerSize) - 1); /* * 6. Further reduce the DCT. This is the magic step. Set the 64 hash * bits to 0 or 1 depending on whether each of the 64 DCT values is * above or below the average value. The result doesn't tell us the * actual low frequencies; it just tells us the very-rough relative * scale of the frequencies to the mean. The result will not vary as * long as the overall structure of the image remains the same; this can * survive gamma and color histogram adjustments without a problem. */ StringBuilder hash = new StringBuilder(); for (int x = 0; x < smallerSize; x++) { for (int y = 0; y < smallerSize; y++) { if (x != 0 && y != 0) { hash.append(dctVals[x][y] > avg ? "1" : "0"); } } } return hash.toString(); } private BufferedImage resize(BufferedImage image, int width, int height) { BufferedImage resizedImage = new BufferedImage(width, height, BufferedImage.TYPE_INT_ARGB); Graphics2D g = resizedImage.createGraphics(); g.drawImage(image, 0, 0, width, height, null); g.dispose(); return resizedImage; } private ColorConvertOp colorConvert = new ColorConvertOp( ColorSpace.getInstance(ColorSpace.CS_GRAY), null); private BufferedImage grayscale(BufferedImage img) { colorConvert.filter(img, img); return img; } private static int getBlue(BufferedImage img, int x, int y) { return (img.getRGB(x, y)) & 0xff; } // DCT function stolen from // http://stackoverflow.com/questions/4240490/problems-with-dct-and-idct-algorithm-in-java private double[] c; private void initCoefficients() { c = new double[size]; for (int i = 1; i < size; i++) { c[i] = 1; } c[0] = 1 / Math.sqrt(2.0); } private double[][] applyDCT(double[][] f) { int N = size; double[][] F = new double[N][N]; for (int u = 0; u < N; u++) { for (int v = 0; v < N; v++) { double sum = 0.0; for (int i = 0; i < N; i++) { for (int j = 0; j < N; j++) { sum += Math .cos(((2 * i + 1) / (2.0 * N)) * u * Math.PI) * Math.cos(((2 * j + 1) / (2.0 * N)) * v * Math.PI) * (f[i][j]); } } sum *= ((c[u] * c[v]) / 4.0); F[u][v] = sum; } } return F; } }