import java.util.Arrays;
/**
* Given an array S of n integers, find three integers in S such that the
* sum is closest to a given number, target. Return the sum of the three
* integers. You may assume that each input would have exactly one solution.
*
* For example, given array S = {-1 2 1 -4}, and target = 1.
* The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
*
* Tags: Arrays, Two pointers
*/
class ThreeSumClosest {
public static void main(String[] args) {
}
/**
* Sort and initialize min
* use two pointers to manipulate sums
* update min when closer
* return when min equals to target or all done
*/
public int threeSumClosest(int[] num, int target) {
int closest = 0;
if (num == null) return closest;
Arrays.sort(num);
for (int i = 0; i < num.length && i < 3; i++) closest += num[i];
if (num.length < 3) return closest;
for (int i = 0; i < num.length - 2; i++) {
int j = i + 1;
int k = num.length - 1;
while (j < k) {
int sum = num[i] + num[j] + num[k];
if (Math.abs(target - sum) < Math.abs(target - closest)) {
closest = sum; // sum is even closer
if (closest == target) return closest; // sum == target
}
if (sum > target) k--;
else j++;
}
}
return closest;
}
}