/** * Given a sorted positive integer array nums and an integer n, add/patch elements to the array such that any number in * range [1, n] inclusive can be formed by the sum of some elements in the array. * Return the minimum number of patches required. * * Example 1: * nums = [1, 3], n = 6 * Return 1. * * Combinations of nums are [1], [3], [1,3], which form possible sums of: 1, 3, 4. * Now if we add/patch 2 to nums, the combinations are: [1], [2], [3], [1,3], [2,3], [1,2,3]. * Possible sums are 1, 2, 3, 4, 5, 6, which now covers the range [1, 6]. * So we only need 1 patch. * * Example 2: * nums = [1, 5, 10], n = 20 * Return 2. * The two patches can be [2, 4]. * * Example 3: * nums = [1, 2, 2], n = 5 * Return 0. * * Tags: Greedy */ public class PatchingArray { /** * Build the largest range possible and find the smallest missing number * if missing >= nums[i], range can be extended to missing + nums[i] * else add missing number, range can be extended to missing * 2 * stop till missing > n */ public int minPatches(int[] nums, int n) { int total = 0, i = 0; for (long miss = 1; miss <= n; total++) { miss += (i < nums.length && nums[i] <= miss) ? nums[i++] : miss; } return total - i; } }