/** * Given a 2D matrix <i>matrix</>, find the sum of the elements inside the rectangle defined by its upper left corner * (row1, * col1) and lower right corner (row2, col2). * <p> * Range Sum Query 2D * The above rectangle (with the red border) is defined by (row1, col1) = (2, 1) and (row2, col2) = (4, 3), which * contains sum = 8. * <p> * Example: * Given matrix = [ * [3, 0, 1, 4, 2], * [5, 6, 3, 2, 1], * [1, 2, 0, 1, 5], * [4, 1, 0, 1, 7], * [1, 0, 3, 0, 5] * ] * <p> * sumRegion(2, 1, 4, 3) -> 8 * sumRegion(1, 1, 2, 2) -> 11 * sumRegion(1, 2, 2, 4) -> 12 * <p> * Note: * You may assume that the matrix does not change. * There are many calls to sumRegion function. * You may assume that row1 ≤ row2 and col1 ≤ col2. * <p> * Tags: Dynamic Programming * Similar Problems: (E) Range Sum Query - Immutable, (H) Range Sum Query 2D - Mutable */ public class RangeSumQuery2DImmutable { public class NumMatrix { /** * Pre-compute sum from (0, 0) to current point in another matrix * Sum from (0, 0) to (row, col) is A + B - C + D * 1. A: sum from (0, 0) to (row - 1, col) * 2. B: sum from (0, 0) to (row, col - 1) * 3. C: sum from (0, 0) to (row - 1, col - 1) * 4. D: sum from (row ,col) to (row, col), which is matrix[row][col] itself * C is added twice in A and B */ private int[][] dp; public NumMatrix(int[][] matrix) { if (matrix == null || matrix.length == 0 || matrix[0].length == 0) return; // Make dp one row and one column bigger than matrix to avoid trivial range validation dp = new int[matrix.length + 1][matrix[0].length + 1]; for (int r = 0; r < matrix.length; r++) { for (int c = 0; c < matrix[0].length; c++) { dp[r + 1][c + 1] = dp[r + 1][c] + dp[r][c + 1] + matrix[r][c] - dp[r][c]; } } } /** * A: Sum of (0, 0) to (row2, col2) is dp[row2 + 1][col2 + 1] * B: Sum of (0, 0) to (row1 - 1, col2) is dp[row1][col2 + 1] * C: Sum of (0, 0) to (row2, col1 - 1) is dp[row2 + 1][col1] * D: Sum of (0, 0) to (row1 - 1, col1 - 1) is dp[row1][col1] * Range sum is A - B - C + D (D is subtracted twice in B and C) */ public int sumRegion(int row1, int col1, int row2, int col2) { return dp[row2 + 1][col2 + 1] - dp[row1][col2 + 1] - dp[row2 + 1][col1] + dp[row1][col1]; } } // Your NumMatrix object will be instantiated and called as such: // NumMatrix numMatrix = new NumMatrix(matrix); // numMatrix.sumRegion(0, 1, 2, 3); // numMatrix.sumRegion(1, 2, 3, 4); }