/* * ModeShape (http://www.modeshape.org) * * Licensed under the Apache License, Version 2.0 (the "License"); * you may not use this file except in compliance with the License. * You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. */ package org.modeshape.jcr; import static org.hamcrest.core.Is.is; import static org.hamcrest.core.IsNot.not; import static org.hamcrest.core.IsNull.notNullValue; import static org.junit.Assert.assertThat; import static org.mockito.Mockito.mock; import java.util.HashSet; import java.util.Set; import org.junit.After; import org.junit.Before; import org.junit.Test; import org.modeshape.jcr.value.binary.BinaryStore; public class ExecutionContextTest { private ExecutionContext context; @Before public void beforeEach() { context = new ExecutionContext(); } @After public void afterEach() { context = null; } @Test public void shouldHaveIdentifierThatIsNotNull() { assertThat(context.getId(), is(notNullValue())); } @Test public void shouldHaveIdentifierThatIsNotBlank() { assertThat(context.getId().length(), is(not(0))); assertThat(context.getId().trim().length(), is(not(0))); } @Test public void shouldHaveIdentifierThatIsUnique() { // Can't really test this, but we certainly can test that there are no duplicates in many contexts ... Set<String> ids = new HashSet<String>(); for (int i = 0; i != 50; ++i) { assertThat(ids.add(new ExecutionContext().getId()), is(true)); } } @Test public void shouldCreateSubcontextsWithDifferentIdentifiers() { ExecutionContext newContext = context.with(mock(BinaryStore.class)); assertThat(newContext.getId(), is(not(context.getId()))); } }