/*
* ModeShape (http://www.modeshape.org)
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file except in compliance with the License.
* You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
*/
package org.modeshape.jcr;
import static org.hamcrest.core.Is.is;
import static org.hamcrest.core.IsNot.not;
import static org.hamcrest.core.IsNull.notNullValue;
import static org.junit.Assert.assertThat;
import static org.mockito.Mockito.mock;
import java.util.HashSet;
import java.util.Set;
import org.junit.After;
import org.junit.Before;
import org.junit.Test;
import org.modeshape.jcr.value.binary.BinaryStore;
public class ExecutionContextTest {
private ExecutionContext context;
@Before
public void beforeEach() {
context = new ExecutionContext();
}
@After
public void afterEach() {
context = null;
}
@Test
public void shouldHaveIdentifierThatIsNotNull() {
assertThat(context.getId(), is(notNullValue()));
}
@Test
public void shouldHaveIdentifierThatIsNotBlank() {
assertThat(context.getId().length(), is(not(0)));
assertThat(context.getId().trim().length(), is(not(0)));
}
@Test
public void shouldHaveIdentifierThatIsUnique() {
// Can't really test this, but we certainly can test that there are no duplicates in many contexts ...
Set<String> ids = new HashSet<String>();
for (int i = 0; i != 50; ++i) {
assertThat(ids.add(new ExecutionContext().getId()), is(true));
}
}
@Test
public void shouldCreateSubcontextsWithDifferentIdentifiers() {
ExecutionContext newContext = context.with(mock(BinaryStore.class));
assertThat(newContext.getId(), is(not(context.getId())));
}
}