/* * Copyright (C) 2008 The Android Open Source Project * * Licensed under the Apache License, Version 2.0 (the "License"); you may not * use this file except in compliance with the License. You may obtain a copy of * the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, WITHOUT * WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the * License for the specific language governing permissions and limitations under * the License. */ package com.s16.inputmethod.skeyboard; /** * Abstract base class for a dictionary that can do a fuzzy search for words based on a set of key * strokes. */ abstract public class Dictionary { /** * Whether or not to replicate the typed word in the suggested list, even if it's valid. */ protected static final boolean INCLUDE_TYPED_WORD_IF_VALID = false; /** * The weight to give to a word if it's length is the same as the number of typed characters. */ protected static final int FULL_WORD_FREQ_MULTIPLIER = 2; public static enum DataType { UNIGRAM, BIGRAM } /** * Interface to be implemented by classes requesting words to be fetched from the dictionary. * @see #getWords(WordComposer, WordCallback) */ public interface WordCallback { /** * Adds a word to a list of suggestions. The word is expected to be ordered based on * the provided frequency. * @param word the character array containing the word * @param wordOffset starting offset of the word in the character array * @param wordLength length of valid characters in the character array * @param frequency the frequency of occurence. This is normalized between 1 and 255, but * can exceed those limits * @param dicTypeId of the dictionary where word was from * @param dataType tells type of this data * @return true if the word was added, false if no more words are required */ boolean addWord(char[] word, int wordOffset, int wordLength, int frequency, int dicTypeId, DataType dataType); } /** * Searches for words in the dictionary that match the characters in the composer. Matched * words are added through the callback object. * @param composer the key sequence to match * @param callback the callback object to send matched words to as possible candidates * @param nextLettersFrequencies array of frequencies of next letters that could follow the * word so far. For instance, "bracke" can be followed by "t", so array['t'] will have * a non-zero value on returning from this method. * Pass in null if you don't want the dictionary to look up next letters. * @see WordCallback#addWord(char[], int, int) */ abstract public void getWords(final WordComposer composer, final WordCallback callback, int[] nextLettersFrequencies); /** * Searches for pairs in the bigram dictionary that matches the previous word and all the * possible words following are added through the callback object. * @param composer the key sequence to match * @param callback the callback object to send possible word following previous word * @param nextLettersFrequencies array of frequencies of next letters that could follow the * word so far. For instance, "bracke" can be followed by "t", so array['t'] will have * a non-zero value on returning from this method. * Pass in null if you don't want the dictionary to look up next letters. */ public void getBigrams(final WordComposer composer, final CharSequence previousWord, final WordCallback callback, int[] nextLettersFrequencies) { // empty base implementation } /** * Checks if the given word occurs in the dictionary * @param word the word to search for. The search should be case-insensitive. * @return true if the word exists, false otherwise */ abstract public boolean isValidWord(CharSequence word); /** * Compares the contents of the character array with the typed word and returns true if they * are the same. * @param word the array of characters that make up the word * @param length the number of valid characters in the character array * @param typedWord the word to compare with * @return true if they are the same, false otherwise. */ protected boolean same(final char[] word, final int length, final CharSequence typedWord) { if (typedWord.length() != length) { return false; } for (int i = 0; i < length; i++) { if (word[i] != typedWord.charAt(i)) { return false; } } return true; } /** * Override to clean up any resources. */ public void close() { } }