// Copyright (c) 2003-present, Jodd Team (http://jodd.org)
// All rights reserved.
//
// Redistribution and use in source and binary forms, with or without
// modification, are permitted provided that the following conditions are met:
//
// 1. Redistributions of source code must retain the above copyright notice,
// this list of conditions and the following disclaimer.
//
// 2. Redistributions in binary form must reproduce the above copyright
// notice, this list of conditions and the following disclaimer in the
// documentation and/or other materials provided with the distribution.
//
// THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS "AS IS"
// AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
// IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
// ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT HOLDER OR CONTRIBUTORS BE
// LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR
// CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF
// SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS
// INTERRUPTION) HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN
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package org.springside.modules.utils.text;
import org.apache.commons.lang3.StringUtils;
import org.springside.modules.utils.base.Platforms;
/**
*
* 从Jodd移植，匹配以通配符比较字符串（比正则表达式简单），以及Ant Path风格如比较目录Path
*
* Checks whether a string or path matches a given wildcard pattern. Possible patterns allow to match single characters
* ('?') or any count of characters ('*'). Wildcard characters can be escaped (by an '\'). When matching path, deep tree
* wildcard also can be used ('**').
* <p>
* This method uses recursive matching, as in linux or windows. regexp works the same. This method is very fast,
* comparing to similar implementations.
*/
public class WildcardMatcher {
/**
* Checks whether a string matches a given wildcard pattern.
*
* @param string input string
* @param pattern pattern to match
* @return <code>true</code> if string matches the pattern, otherwise <code>false</code>
*/
public static boolean match(CharSequence string, CharSequence pattern) {
return match(string, pattern, 0, 0);
}
/**
* Internal matching recursive function.
*/
private static boolean match(CharSequence string, CharSequence pattern, int sNdx, int pNdx) {
int pLen = pattern.length();
if (pLen == 1) {
if (pattern.charAt(0) == '*') { // speed-up
return true;
}
}
int sLen = string.length();
boolean nextIsNotWildcard = false;
while (true) {
// check if end of string and/or pattern occurred
if ((sNdx >= sLen)) { // end of string still may have pending '*' in pattern
while ((pNdx < pLen) && (pattern.charAt(pNdx) == '*')) {
pNdx++;
}
return pNdx >= pLen;
}
if (pNdx >= pLen) { // end of pattern, but not end of the string
return false;
}
char p = pattern.charAt(pNdx); // pattern char
// perform logic
if (!nextIsNotWildcard) {
if (p == '\\') {
pNdx++;
nextIsNotWildcard = true;
continue;
}
if (p == '?') {
sNdx++;
pNdx++;
continue;
}
if (p == '*') {
char pNext = 0; // next pattern char
if (pNdx + 1 < pLen) {
pNext = pattern.charAt(pNdx + 1);
}
if (pNext == '*') { // double '*' have the same effect as one '*'
pNdx++;
continue;
}
int i;
pNdx++;
// find recursively if there is any substring from the end of the
// line that matches the rest of the pattern !!!
for (i = string.length(); i >= sNdx; i--) {
if (match(string, pattern, i, pNdx)) {
return true;
}
}
return false;
}
} else {
nextIsNotWildcard = false;
}
// check if pattern char and string char are equals
if (p != string.charAt(sNdx)) {
return false;
}
// everything matches for now, continue
sNdx++;
pNdx++;
}
}
// ---------------------------------------------------------------- utilities
/**
* Matches string to at least one pattern. Returns index of matched pattern, or <code>-1</code> otherwise.
* @see #match(CharSequence, CharSequence)
*/
public static int matchOne(String src, String[] patterns) {
for (int i = 0; i < patterns.length; i++) {
if (match(src, patterns[i])) {
return i;
}
}
return -1;
}
/**
* Matches path to at least one pattern. Returns index of matched pattern or <code>-1</code> otherwise.
* @see #matchPath(String, String)
*/
public static int matchPathOne(String path, String[] patterns) {
for (int i = 0; i < patterns.length; i++) {
if (matchPath(path, patterns[i])) {
return i;
}
}
return -1;
}
// ---------------------------------------------------------------- path
protected static final String PATH_MATCH = "**";
protected static final String PATH_SEPARATORS = "/\\";
/**
* Matches path against pattern using *, ? and ** wildcards. Both path and the pattern are tokenized on path
* separators (both \ and /). '**' represents deep tree wildcard, as in Ant.
*/
public static boolean matchPath(String path, String pattern) {
String[] pathElements = StringUtils.split(path, Platforms.FILE_PATH_SEPARATOR_CHAR);
String[] patternElements = StringUtils.split(pattern, Platforms.FILE_PATH_SEPARATOR_CHAR);
return matchTokens(pathElements, patternElements);
}
/**
* Match tokenized string and pattern.
*/
protected static boolean matchTokens(String[] tokens, String[] patterns) {
int patNdxStart = 0;
int patNdxEnd = patterns.length - 1;
int tokNdxStart = 0;
int tokNdxEnd = tokens.length - 1;
while ((patNdxStart <= patNdxEnd) && (tokNdxStart <= tokNdxEnd)) { // find first **
String patDir = patterns[patNdxStart];
if (patDir.equals(PATH_MATCH)) {
break;
}
if (!match(tokens[tokNdxStart], patDir)) {
return false;
}
patNdxStart++;
tokNdxStart++;
}
if (tokNdxStart > tokNdxEnd) {
for (int i = patNdxStart; i <= patNdxEnd; i++) { // string is finished
if (!patterns[i].equals(PATH_MATCH)) {
return false;
}
}
return true;
}
if (patNdxStart > patNdxEnd) {
return false; // string is not finished, but pattern is
}
while ((patNdxStart <= patNdxEnd) && (tokNdxStart <= tokNdxEnd)) { // to the last **
String patDir = patterns[patNdxEnd];
if (patDir.equals(PATH_MATCH)) {
break;
}
if (!match(tokens[tokNdxEnd], patDir)) {
return false;
}
patNdxEnd--;
tokNdxEnd--;
}
if (tokNdxStart > tokNdxEnd) {
for (int i = patNdxStart; i <= patNdxEnd; i++) { // string is finished
if (!patterns[i].equals(PATH_MATCH)) {
return false;
}
}
return true;
}
while ((patNdxStart != patNdxEnd) && (tokNdxStart <= tokNdxEnd)) {
int patIdxTmp = -1;
for (int i = patNdxStart + 1; i <= patNdxEnd; i++) {
if (patterns[i].equals(PATH_MATCH)) {
patIdxTmp = i;
break;
}
}
if (patIdxTmp == patNdxStart + 1) {
patNdxStart++; // skip **/** situation
continue;
}
// find the pattern between padIdxStart & padIdxTmp in str between strIdxStart & strIdxEnd
int patLength = (patIdxTmp - patNdxStart - 1);
int strLength = (tokNdxEnd - tokNdxStart + 1);
int ndx = -1;
strLoop: for (int i = 0; i <= strLength - patLength; i++) {
for (int j = 0; j < patLength; j++) {
String subPat = patterns[patNdxStart + j + 1];
String subStr = tokens[tokNdxStart + i + j];
if (!match(subStr, subPat)) {
continue strLoop;
}
}
ndx = tokNdxStart + i;
break;
}
if (ndx == -1) {
return false;
}
patNdxStart = patIdxTmp;
tokNdxStart = ndx + patLength;
}
for (int i = patNdxStart; i <= patNdxEnd; i++) {
if (!patterns[i].equals(PATH_MATCH)) {
return false;
}
}
return true;
}
}